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Fractions Test - 21

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Fractions Test - 21
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  • Question 1
    1 / -0
    Which of the following fraction is located at the point $$A$$ on the number line?

    Solution
    $$A=$$ $$\dfrac{3}{8}$$
  • Question 2
    1 / -0
    On the basis of given number line, the reasonable value for $$B$$ is ____.

    Solution
    $$B=$$ $$\dfrac{1}{6}$$
  • Question 3
    1 / -0
    Which of the following number line is corresponds to the fraction represented by the shaded portion?

    Solution
    $$2$$ out of $$4$$ is shaded 
    $$\therefore\dfrac{2}{4}$$
  • Question 4
    1 / -0
    Identify the number represented by the given number line.

    Solution
    the fraction is $$\dfrac{1}{6}$$
  • Question 5
    1 / -0
    Which of the following number line is corresponds to the fraction represented by the shaded portion?

    Solution
    $$4 $$ out of $$8$$ is shaded
    $$\therefore \dfrac{4}{8}$$
  • Question 6
    1 / -0
    Use the number line below to determine which fraction belongs in the box.

    Solution
    the number is $$\dfrac{1}{2}$$
  • Question 7
    1 / -0
    $$\displaystyle \frac {5}{8}\, -\, \displaystyle \frac {2}{8}\, =$$ ...........
    Solution
    Let us first consider the given subtraction of the fractions as follows:

    $$\dfrac { 5}{ 8 } -\dfrac { 2 }{ 8 }=\dfrac { 3 }{ 8 }$$

    The fraction $$\dfrac { 3 }{ 8 }$$ means that we need to determine that circular object which is divided in $$8$$ equal triangles and $$3$$ triangles should be shaded amongst them.

    Hence, the circular object with the fraction $$\dfrac { 3 }{ 8 }$$ is shown in the figure 

  • Question 8
    1 / -0
    Example for an improper fraction is
    Solution
    Improper fraction is a fraction in which the numerator is greater than the denominator.

    Hence, $$\dfrac {15}{14}$$ is an improper fraction.
  • Question 9
    1 / -0
    The difference between the greatest and least numbers of $$\displaystyle {\frac{5}{9},\, \frac{1}{9},\, \frac{11}{9}}$$ is 
    Solution
    Amongst the given fractions $$\dfrac {5}{9},\dfrac {1}{9}$$ and $$\dfrac {11}{9}$$, the smallest is $$\dfrac {1}{9}$$ and the largest is $$\dfrac {11}{9}$$.

    Now, consider the subtraction of the greatest and least fraction as follows:

    $$\dfrac { 11 }{ 9 } -\dfrac { 1 }{ 9 } =\dfrac { 10 }{ 9 }$$

    Hence, the difference between the greatest and least numbers is $$\dfrac {10}{9}$$.
  • Question 10
    1 / -0
    $$2 - \displaystyle \frac{11}{39} + \frac{5}{26}$$ = ..........
    Solution
    $$\displaystyle \frac{2}{1} - \frac{11}{39} + \frac{5}{26}$$
    $$= \displaystyle \frac{156 - 22 + 15}{78} = \frac{149}{78} == 1 + \frac{71}{78}$$
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