Fractions Test

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Fractions Test - 25

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Weekly Quiz Competition

Question 1
1 / -0

Solve : $$\dfrac {1}{4}-\left(\dfrac {1}{4}\right)$$

A
$$1$$

B
$$\dfrac {2}{4}$$

C
$$\dfrac {-3}{4}$$

D
$$0$$

Solution

$$\dfrac{1}{4}-\left(\dfrac{1}{4}\right)$$.

$$=\dfrac{1}{4}-\dfrac{1}{4}=0$$
Question 2
1 / -0

A proper fraction with denominator $$3$$ , which is less than 1 is

A
$$\frac{4}{3}$$

B
$$\frac{2}{3}$$

C
$$1 \frac{2}{3}$$

D
None

Solution

Clearly from question denominator$$=3$$
numerator $$=2$$
Fraction $$=\dfrac{2}{3}$$
Question 3
1 / -0

A fraction whose numerator is greater than its denominator is fraction.

A
an improper

B
a proper

C
a mixed

D
None of these

Solution

That will be an improper fraction
Ex $$\dfrac{6}{5}$$
Question 4
1 / -0

The value of $$\dfrac 12+\dfrac 13+\dfrac 14$$

A
$$\dfrac {13}{12}$$

B
$$\dfrac1 {15}$$

C
$$\dfrac 1{12}$$

D
$$\dfrac 1{24}$$

Solution

$$\dfrac 12+\dfrac 1 3+\dfrac 14$$

$$=\dfrac{6+4+3}{12}$$

$$=\dfrac{13}{12}$$
Question 5
1 / -0

$$289/391$$ when reduced to the lowest terms is

A
$$11 / 23$$

B
$$13 / 31$$

C
$$17 / 31$$

D
$$17 / 23$$

Solution

Dividing both numerator and denominator by the HCF of $$289 / 391$$
Hence $$289 / 391 = 17 / 23$$
$$17 / 23$$ is the correct answer
Option (d) is the correct answer
Question 6
1 / -0

Mark the correct answer in the following:
The ratio $$92:115$$ in its simplest form is

A
$$23:25$$

B
$$18:23$$

C
$$3:5$$

D
$$4:5$$

Solution

Since $$HCF$$ of $$92$$ and $$115$$ is $$23$$
$$\therefore 92:115$$
$$=\dfrac{92}{115}$$
$$=\dfrac{(92\div 23)}{ (115\div 23)}$$
$$=\dfrac45$$
$$=4:5$$

Hence option (D) is correct answer.
Question 7
1 / -0

Which of the following is a proper fraction?

A
$$\dfrac78$$

B
$$1\dfrac{7}{8}$$

C
$$\dfrac87$$

D
none of these

Solution

We know that, if the numerator is less than the denominator then the fraction is called as proper fraction.
Amongst the given fractions only $$\dfrac78$$ has a numerator that is less than the denominator.

Hence, $$\dfrac78$$ is a proper fraction.
Question 8
1 / -0

Write $$-\dfrac{33}{55}$$ in standard form

A
$$\dfrac{3}{5}$$

B
$$-\dfrac{3}{5}$$

C
$$-\dfrac{33}{55}$$

D
$$None\ of\ these$$

Solution

$$(B) (-3/5)$$
Because,
We write $$-\dfrac{33}{55}$$ in standard form as

$$=-\dfrac{3\times 11}{5\times 11}$$

$$=-\dfrac{3}{5}$$
Question 9
1 / -0

Write $$-\dfrac{102}{119}$$ in standard form

A
$$\dfrac{6}{7}$$

B
$$-\dfrac{6}{7}$$

C
$$\dfrac{6}{17}$$

D
None of these

Solution

To write the given fraction in standard form first write numerator and denominator as product of its prime factors and then by cancelling the common factors from we will get standard form,

$$\begin{aligned}{} - \frac{{102}}{{119}} &= - \frac{{17 \times 2\times3}}{{17 \times 7}}\\\\& = - \dfrac{6}{7}\end{aligned}$$

Hence, option $$B$$ is correct.
Question 10
1 / -0

Which of the following is an improper fraction?

A
$$\dfrac{7}{10}$$

B
$$\dfrac{7}{9}$$

C
$$\dfrac{9}{7}$$

D
none of these

Solution

Improper fraction is a fraction in which numerator is greater than denominator.
$$\cfrac{9}{7}$$ follows this condition.
Hence, option $$(C)$$ is correct.

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Re-Attempt Weekly Quiz Competition

Fractions Test - 25

Result

Fractions Test - 25

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SHARING IS CARING

Question 1

$$1$$

$$\dfrac {2}{4}$$

$$\dfrac {-3}{4}$$

$$0$$

Solution

Question 2

$$\frac{4}{3}$$

$$\frac{2}{3}$$

$$1 \frac{2}{3}$$

None

Solution

Question 3

an improper

a proper

a mixed

None of these

Solution

Question 4

$$\dfrac {13}{12}$$

$$\dfrac1 {15}$$

$$\dfrac 1{12}$$

$$\dfrac 1{24}$$

Solution

Question 5

$$11 / 23$$

$$13 / 31$$

$$17 / 31$$

$$17 / 23$$

Solution

Question 6

$$23:25$$

$$18:23$$

$$3:5$$

$$4:5$$

Solution

Question 7

$$\dfrac78$$

$$1\dfrac{7}{8}$$

$$\dfrac87$$

none of these

Solution

Question 8

$$\dfrac{3}{5}$$

$$-\dfrac{3}{5}$$

$$-\dfrac{33}{55}$$

$$None\ of\ these$$

Solution

Question 9

$$\dfrac{6}{7}$$

$$-\dfrac{6}{7}$$

$$\dfrac{6}{17}$$

None of these

Solution

Question 10

$$\dfrac{7}{10}$$

$$\dfrac{7}{9}$$

$$\dfrac{9}{7}$$

none of these

Solution

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