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Decimals Test - 2

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Decimals Test - 2
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  • Question 1
    1 / -0

    Prerna had Rs.5000. She bought 2 boxes of chocolates for Rs.52.98 each, 3 packets of chips for Rs.12.98 each and 2 books for Rs.300.05 each. How much money left with her?

    Solution

    Total expenditure= Rs. 2×52.98)+ (3×12.98)+(2×300.05 = Rs. (105.96 + 38.94 + 600.10) = Rs. 745 Amount of money left with her = Rs. (5000 - 745)= Rs. 4255

  • Question 2
    1 / -0

    Select the INCORRECT statement.

    Solution

    (a) Total length of cloth Tina had = 1556 cm = 15.56 m

    Length of cloth she cut from it = 13 m 50 cm = 13.50 m

    ∴ Length of cloth left with her

    =15.56−13.50

    = 2.06 m

    (b) Total weight of vegetables Neetu bought

    = 500 g + 250 g + 700 g + 500 g + 100 g + 300 g

    = 2350 g i.e., 2.350 kg

    (c) Total amount spent by Rita

    = Rs. (117.35 + 50.75) = Rs. 168.10

    Amount left with Rita = Rs. (500 - 168.10)

    = Rs. 331.90

    (d) Total distance covered by Yashika

    = 20 km 50 m = 20.050 km

    Distance covered by auto = 20.050 - (1 +15)

    = 20.050- 16 = 4.05 km

  • Question 3
    1 / -0

    Select the INCORRECT statement.

    Solution

    (a) Total length of cloth Tina had = 1556 cm = 15.56 m

    Length of cloth she cut from it = 13 m 50 cm = 13.50 m

    ∴ Length of cloth left with her

    =15.56−13.50

    = 2.06 m

    (b) Total weight of vegetables Neetu bought

    = 500 g + 250 g + 700 g + 500 g + 100 g + 300 g

    = 2350 g i.e., 2.350 kg

    (c) Total amount spent by Rita

    = Rs. (117.35 + 50.75) = Rs. 168.10

    Amount left with Rita = Rs. (500 - 168.10)

    = Rs. 331.90

    (d) Total distance covered by Yashika

    = 20 km 50 m = 20.050 km

    Distance covered by auto = 20.050 - (1 +15)

    = 20.050- 16 = 4.05 km

  • Question 4
    1 / -0

    Arrange the following decimal numbers in ascending order. 3.6, 3.06, 3.306, 0.306

    Solution

    The ascending order is, 0.306, 3.06, 3.306, 3.6

  • Question 5
    1 / -0

    Abhishek had Rs.817.45. He bought toys for Rs.538.30. The balance amount left with Abhishek is ________.

    Solution

    Amount of money Abhishek had = Rs. 817.45 Amount of money spent by him on toys = Rs. 538.30 ∴ Amount of money left with him = Rs. (817.45-538.30) = Rs. 279.15

  • Question 6
    1 / -0

    Sumeet purchased a book costing Rs. 24.75 and a pencil box. If he got back Rs. 32.75 when he gave a Rs. 100 note, what is the cost of the pencil box?

    Solution

    Cost of a book = Rs. 24.75 Cost of a book and a pencil box Rs. (100 - 32.75) = Rs. 67.25 Cost of pencil box = Rs. (67.25 - 24.75) = Rs. 42.50

  • Question 7
    1 / -0

    0.75 of a number is 1200. What is 5/8 of that number?

    Solution

    Let the required number be x. According to question, 0.75 of x = 1200 ⇒ 75/100 × x = 1200 ⇒ x = 1200 × 100/75 = 1600 ∴ Required number =1600 Now, 5/8 of the number = 5/8 × 1600 = 1000

  • Question 8
    1 / -0

    Rahul purchased 4 kg 500 g rice, 5 kg 650 g sugar and 12 kg 600 g at ta. The total weight of his purchases was ________.

    Solution

    Weight of rice = 4 kg 500 g = 4.500 kg Weight of sugar = 5 kg 650 g = 5.650 kg Weight of atta = 12 kg 600 g = 12.600 kg ∴ Total weight of all items = (4.500 + 5.650 + 12.600) kg = 22.750 kg

  • Question 9
    1 / -0

    Prem went to a craft fair where he spent a total of Rs.16.00. He spent Rs.6.00 on admission and went to 8 tables. He spent the same amount of money (m) at each table. The given expression can be used to find how much money he spent at each table. 16 = 6 + 8 m. How much money did Prem spent at each table?

    Solution

    We have, 16 = 6 + 8 m ⇒ 8m = 16−6=10
    ⇒ m = 10/8 = 1.25 So, Prem spent Rs. 1.25 at each table.

  • Question 10
    1 / -0

    If 0.090909 is approximately equal to 1/11, then the approximate value of 0.454545 is______.

    Solution

    We have, 0.090909=1/11 Now, 0.090909×5 = 1/11 × 5 ⇒ 0.454545 = 5/11

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