Decimals Test

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Decimals Test - 8

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Weekly Quiz Competition

Question 1
1 / -0

$$685.59 - x = 607.88 - 351.46$$

A
$$449.28$$

B
$$419.17$$

C
$$429.17$$

D
$$439.28$$

Solution

Given that : $$685.59 - x = 607.88 - 351.46$$
Therefore, $$x = 685.59 - 607.88 + 351.46 = 429.17$$
Question 2
1 / -0

Evaluate : $$88.8 + 8.08 + 0.08 + 88.08 + 0.80 + 888$$.

A
$$1073.84$$

B
$$1073.76$$

C
$$1073.04$$

D
None of these

Solution

$$88.80$$
+ $$8.08$$
+ $$0.08$$
+ $$88.08$$
+ $$0.80$$
+ $$888.00$$
_________
$$1073.84$$
_________
$$\therefore$$ Required sum $$= 1073.84$$.
Question 3
1 / -0

Expanded form of 92083.1

A
9000 + 20000 + 80 + 1

B
9200 + 80 + 31

C
90000 + 2000 + 800 + 30 + 1

D
90000 + 2000 + 80 + 3 + 0.1

Solution

Expanded form of 92083.1
$$90000+2000+80+3+0.1$$
Question 4
1 / -0

Expanded form of 34.059 is

A
$$34\,+\, \displaystyle\frac{5}{10}\,+\, \frac{9}{100}$$

B
$$30\,+\, 4\, +\, \displaystyle\frac{5}{100}\,+\, \frac{9}{1000}$$

C
$$3\,+\, 4\,+\,\displaystyle\frac{5}{10}\,+\, \frac{9}{100}$$

D
None of these

Solution

Expanded form of $$34.059$$ is $$ 30+4+0+\displaystyle \frac{5}{100} + \frac{9}{1000}$$
Question 5
1 / -0

Evaluate : $$0.75 - 0.0075$$.

A
$$0.7405$$

B
$$0.7425$$

C
$$0.7415$$

D
$$0.7525$$

Solution

$$0.7500$$
$$- 0.0075$$
_________
$$0.7425$$
_________
$$\therefore$$ Required difference $$= 0.7425$$.
Question 6
1 / -0

Evaluate the missing term:
$$301.01 - 0.101 =$$ ___ $$+ 198.01$$

A
$$103.119$$

B
$$103.101$$

C
$$102.901$$

D
$$102.899$$

Solution

Requried number $$ = 301.01 - 0.101 - 198.01$$
$$= 301.01 - 198.111 = 102.899$$
Question 7
1 / -0

A shopkeeper sold $$12.750$$ kg of sugar one a day. On the next day he sold $$38.250$$ kg of sugar. On the third day he sold $$50.500$$ kg of sugar. How much of sugar in all did the shopkeeper sell altogether?

A
$$100$$ kg

B
$$202.5$$ kg

C
$$102.5$$ kg

D
$$101.5$$ kg

Solution

Sugar sold by the shopkeeper on the first day = $$12.750 \ \ kg$$
Sugar sold by the shopkeeper on the second day = $$38.250 \ \ kg$$
Sugar sold by the shopkeeper on the third day = $$50.500 \ \ kg$$
Hence the shopkeeper sold = $$(12. 750 + 38. 250 + 50.500) \ \ \ kg = 101.5 \ \ kg$$
Question 8
1 / -0

$$4\, +\, \displaystyle \frac{3}{100}\, =$$ ..........

A
43

B
4.3

C
4.03

D
0.43

Solution

$$4\, +\, \displaystyle \frac{3}{100}\, =\dfrac{400+3}{100}=4.03$$ Hence the answer is option C
Question 9
1 / -0

Evaluate the expression $$\displaystyle 1.5625+0.75-0.3125$$

A
$$5.9375$$

B
$$4.2968$$

C
$$2.1250$$

D
$$2$$

Solution

$$1.5625 + 0.75 - 0.3125$$
$$= 2.3125 - 0.3125 = 2$$
Question 10
1 / -0

Simplified value for $$12.500 + 8.75 + 2.25$$ is

A
$$23.500$$

B
$$13.600$$

C
$$13600$$

D
$$23.050$$

Solution

Given that we have to find the sum of three numbers

$$ 12.500 , 8.75 , 2.25 $$

$$8.75+2.25 = 11.00$$

$$12.500+8.75+2.25 = 12.500+11.000 = 23.500$$

So Option $$A$$ is correct

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Decimals Test - 8

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Decimals Test - 8

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Question 1

$$449.28$$

$$419.17$$

$$429.17$$

$$439.28$$

Solution

Question 2

$$1073.84$$

$$1073.76$$

$$1073.04$$

None of these

Solution

Question 3

9000 + 20000 + 80 + 1

9200 + 80 + 31

90000 + 2000 + 800 + 30 + 1

90000 + 2000 + 80 + 3 + 0.1

Solution

Question 4

$$34\,+\, \displaystyle\frac{5}{10}\,+\, \frac{9}{100}$$

$$30\,+\, 4\, +\, \displaystyle\frac{5}{100}\,+\, \frac{9}{1000}$$

$$3\,+\, 4\,+\,\displaystyle\frac{5}{10}\,+\, \frac{9}{100}$$

None of these

Solution

Question 5

$$0.7405$$

$$0.7425$$

$$0.7415$$

$$0.7525$$

Solution

Question 6

$$103.119$$

$$103.101$$

$$102.901$$

$$102.899$$

Solution

Question 7

$$100$$ kg

$$202.5$$ kg

$$102.5$$ kg

$$101.5$$ kg

Solution

Question 8

43

4.3

4.03

0.43

Solution

Question 9

$$5.9375$$

$$4.2968$$

$$2.1250$$

$$2$$

Solution

Question 10

$$23.500$$

$$13.600$$

$$13600$$

$$23.050$$

Solution

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