Integers Test

Result

Integers Test - 14

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Weekly Quiz Competition

Question 1
1 / -0

Divide:
$$(-60 \times -72) \ by\ (36\times (-15))$$

A
-8

B
-16

C
8

D
16

Solution

Given, $$

\dfrac { (-60)\times (-72) }{ 36\times (-15) } $$

As there are $$ 2 $$ negative numbers in the numerator and $$ 1 $$ in the

denominator, the answer will be negative.

Cancelling out the common factors and simplifying we get

$$ \dfrac { (-60)\times (-72) }{ 36\times (-15) }=-4\times 2 = - 8 $$
Question 2
1 / -0

The value of $$52-27 $$ is

A
$$24$$

B
$$25$$

C
$$26$$

D
$$-24$$

Solution

$$ 52 - 27 = 25 $$
Question 3
1 / -0

The value of $$-5\times-12\times 2\times-3$$ is

A
-360

B
-380

C
-400

D
360

Solution

As there are $$ 3 $$ negative numbers, which is an odd number, the product will be negative.

So, $$ -5 \times -12 \times 2\times -3 = - 360 $$
Question 4
1 / -0

Multiply $$4\times(-3)\times (-2) \ and\ 6\times(-5)$$

A
-720

B
-70

C
-270

D
720

Solution

$$4 \times (-3)\times (-2)\times 6\times (-5)$$
$$=24\times -30$$
$$=-720$$
Question 5
1 / -0

Divide $$96×(−25)\ by\ (−75)×(−16)$$

A
-2

B
2

C
-5

D
5

Solution

$$96\times (-25) \div (-75)\times (-16)$$
$$=-2400\div 1200$$
$$=-2$$
Question 6
1 / -0

Multiply:
$$(-5)\times 8$$ and $$3\times (-2)$$

A
240

B
420

C
-240

D
-420

Solution

$$ (-5)\times 8 = - 40 $$

$$ 3\times (-2) = -6 $$

Hence, $$ ((-5)\times 8 ) \times (3\times (-2)) = -40 \times -6 = 240 $$
Question 7
1 / -0

The value of $$-5\times -2\times -2\times-3$$ is

A
80

B
65

C
60

D
-60

Solution

As there are $$ 4 $$ negative numbers, which is an even number, the product

will be positive.

So, $$ -5 \times -2 \times -2\times -3 = 60 $$
Question 8
1 / -0

The value of $$\displaystyle\ \frac{-18\times 5}{3\times (-10)}$$ is

A
3

B
6

C
4

D
-3

Solution

As there is $$ 1$$ negative number in the numerator and $$ 1 $$ in the

denominator, the answer will be positive.

Cancelling out the common factors and simplifying we get

$$ \dfrac { -18\times 5 }{ 3\times (-10) } = 3 $$
Question 9
1 / -0

Solve $$(-87) + (-35) = $$

A
-122

B
-65

C
-35

D
87

Solution

$$(-87) + (-35)$$
$$(-87-35)$$
$$= -122$$
Question 10
1 / -0

The value of $$\displaystyle\ \frac{15\times (-24)\times(-18)}{-(27)\times (20)}$$ is

A
-16

B
-15

C
-12

D
12

Solution

As there are $$ 2 $$ negative numbers in the numerator and $$ 1 $$ in the denominator, the answer will be negative.

Cancelling out the common factors and simplifying we get

$$ \dfrac { 15\times (-24)\times (-18) }{ -(27)\times (20) } =\dfrac {3 \times 8 \times 18}{-9\times 4}=-3\times 2\times2 = -12 $$

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Re-Attempt Weekly Quiz Competition

Integers Test - 14

Result

Integers Test - 14

Score

-

Rank

-

SHARING IS CARING

Question 1

-8

-16

8

16

Solution

Question 2

$$24$$

$$25$$

$$26$$

$$-24$$

Solution

Question 3

-360

-380

-400

360

Solution

Question 4

-720

-70

-270

720

Solution

Question 5

-2

2

-5

5

Solution

Question 6

240

420

-240

-420

Solution

Question 7

80

65

60

-60

Solution

Question 8

3

6

4

-3

Solution

Question 9

-122

-65

-35

87

Solution

Question 10

-16

-15

-12

12

Solution

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