Integers Test

Result

Integers Test - 23

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Weekly Quiz Competition

Question 1
1 / -0

Find the missing value: $$(-27) \times (-31) = (-31) \times .....$$

A
$$31$$

B
$$(-31)$$

C
$$27$$

D
$$(-27)$$

Solution

Integers are commutative under multiplication. i.e. $$a\times b = b\times a.$$
$$\therefore (-27) \times (-31) = (-31) \times (-27)$$.
Question 2
1 / -0

Find the missing value: $$(-6) \times .... = 8\times (-6)$$

A
$$(-6)$$

B
$$-(8)$$

C
$$8$$

D
$$6$$

Solution

Integers are commutative under multiplication. i.e. $$a\times b = b\times a$$.
$$\therefore $$ Clearly, $$(-6) \times 8 = 8\times (-6)$$.
Question 3
1 / -0

Find the missing value: $$(-6) + (-9) = ...... + (-6)$$

A
$$6$$

B
$$9$$

C
$$-9$$

D
$$-6$$

Solution

$$\textbf{Step - 1: Define Commutative Rule}$$

$$\text{The commutative rule is }, a+b=b+a$$

$$\textbf{Step - 2: Using the rule}$$

$$\text{Given, } (-6) +(-9) = .... + (-6)$$

$$\text{Then, } (-6) + (-9) = (-9) + (-6)$$

$$\textbf{Hence, the missing term is -9.}$$
Question 4
1 / -0

Fill the blank space: $$(-8)\times ...... = 3\times ......$$

A
$$-8, 3$$

B
$$-8, -3$$

C
$$3, -8$$

D
$$-3, -8$$

Solution

Integers are commutative under multiplication. i.e. $$a\times b = b\times a$$.
$$\therefore (-8) \times 3 = 3\times (-8)$$
$$\therefore$$ The missing numbers are $$3, -8$$.
Question 5
1 / -0

Find the missing value: $$(-4) + .... = 7 + (-4)$$

A
$$(-4)$$

B
$$7$$

C
$$4$$

D
$$-7$$

Solution

$$\textbf{Step - 1: Define Commutative Rule}$$

$$\text{The commutative rule is }, a+b=b+a$$

$$\textbf{Step - 2: Using the rule}$$

$$\text{Given, } (-4) +..... = 7 + (-4)$$

$$\text{Then, } (-4) + 7 = 7 + (-4)$$

$$\textbf{ Hence, the missing term is 7 } $$
Question 6
1 / -0

The product $$7\times 317$$ is equal to

A
$$7$$

B
$$317\times 7$$

C
$$317$$

D
$$317 + 7$$

Solution

Whole numbers are commutative under multiplication.
Therefore, $$7\times 317 = 317 \times 7$$.
Question 7
1 / -0

Find the missing value: $$ ...... \times (-16) = (-16) \times 4.$$

A
$$16$$

B
$$-16$$

C
$$4$$

D
$$-4$$

Solution

Integers are commutative under multiplication. i.e. $$a\times b = b\times a.$$
$$\therefore$$ Clearly, $$4\times (-16) = (-16) \times 4$$.
Question 8
1 / -0

Find the missing value: $$13\times (-24) = ..... \times 13$$

A
$$(-24)$$

B
$$24$$

C
$$13$$

D
$$(-13)$$

Solution

Integers are commutative under multiplication. i.e. $$a\times b = b\times a.$$
$$\therefore 13\times (-24) = (-24) \times 13$$.
Question 9
1 / -0

Find the missing value: $$(-7)\times 4 = 4 \times ......$$

A
$$-7$$

B
$$4$$

C
$$-4$$

D
$$7$$

Solution

For any two integers $$a$$ and $$b$$
$$a\times b = b\times a$$
$$\therefore (-7)\times 4 = 4\times (-7)$$
Question 10
1 / -0

Fill in the blank :
$$[(-12) + (-15)] + (-5) = (-12) + [(-15) + .....]$$

A
$$(-12)$$

B
$$(-15)$$

C
$$(-5)$$

D
$$5$$

Solution

Addition is associative for integers
$$i.e. (a + b) + c = a + (b + c)$$
$$\therefore [(-12) + (-15)] + (-5) = (-12) + [(-15) + (-5)]$$
So, $$C$$ is correct.

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Re-Attempt Weekly Quiz Competition

Integers Test - 23

Result

Integers Test - 23

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Question 1

$$31$$

$$(-31)$$

$$27$$

$$(-27)$$

Solution

Question 2

$$(-6)$$

$$-(8)$$

$$8$$

$$6$$

Solution

Question 3

$$6$$

$$9$$

$$-9$$

$$-6$$

Solution

Question 4

$$-8, 3$$

$$-8, -3$$

$$3, -8$$

$$-3, -8$$

Solution

Question 5

$$(-4)$$

$$7$$

$$4$$

$$-7$$

Solution

Question 6

$$7$$

$$317\times 7$$

$$317$$

$$317 + 7$$

Solution

Question 7

$$16$$

$$-16$$

$$4$$

$$-4$$

Solution

Question 8

$$(-24)$$

$$24$$

$$13$$

$$(-13)$$

Solution

Question 9

$$-7$$

$$4$$

$$-4$$

$$7$$

Solution

Question 10

$$(-12)$$

$$(-15)$$

$$(-5)$$

$$5$$

Solution

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