Integers Test

Result

Integers Test - 33

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Weekly Quiz Competition

Question 1
1 / -0

$$(-16) \div 4$$ is not same as

A
$$(-4) \div 16$$

B
$$-(16 \div 4)$$

C
$$16 \div(-4)$$

D
$$-4$$

Solution

$${\textbf{Step -1: Write the equation}}{\textbf{.}}$$
$$\left( { - 16} \right) \div 4$$
$${\textbf{Step -2: Solve the equation}}{\textbf{.}}$$
$$\dfrac{{ - 16}}{4} = - 4$$
$${\text{This is not same as}}$$ $$ - 4 \div 16 = \dfrac{{ - 1}}{4}$$$$.$$
$${\text{Others would give the value as }} - 4.$$
$${\textbf{Hence, the }}$$$${\mathbf{\dfrac{{ - 16}}{4}}}$$$${\textbf{ is not same as }}$$$${\mathbf{\dfrac{{ - 4}}{{16}}.}}$$
Question 2
1 / -0

Multiplication of integers satisfies the property of

A
Closure

B
Commutative

C
Associativity

D
All of these

Solution

Multiplication of integers satisfies the closure, commutative, and associative property.

Hence, option D is correct.
Question 3
1 / -0

Calculate: $$-12-(-7)$$

A
$$5$$

B
$$-5$$

C
$$15$$

D
$$-19$$

Solution

$$ -12 - (-7) $$
$$ = -12 + 7 = -5$$
Question 4
1 / -0

$$(-25)(6+4)$$ is not the same as

A
$$-250$$

B
$$(-25)\times 10$$

C
$$(-25)\times 6\times 4$$

D
$$(-25)\times 6+(-25)\times 4$$

Solution

$$(-25)(6+4)$$ is not same as $$(-25)\times 6\times 4$$ as $$6+4=10$$ but $$6\times 4=24$$
Question 5
1 / -0

$$(-33)\times 102+(-33)\times (-2)$$ is equal to

A
$$3300$$

B
$$-3300$$

C
$$3432$$

D
$$-3432$$

Solution

$$(-33)\times 102+(-33)\times (-2)=(-33)(102-2)=-33\times 100=-3300$$
Question 6
1 / -0

$$0\div (-10)$$ is equal to

A
$$0$$

B
$$-1$$

C
$$-10$$

D
None of these

Solution

We know that, $$0$$ divided by any number is $$0$$
$$\therefore \ 0\div (-10)=\dfrac {0}{-10}=0$$

Hence, option A is correct.
Question 7
1 / -0

Evaluate $$\displaystyle\ \frac {5\times (-144)\times (-27)}{(-15)\times(18)\times(-16)}$$

A
$$\dfrac {9}{4}$$

B
$$\dfrac {9}{8}$$

C
$$\dfrac {9}{2}$$

D
$$\dfrac {-9}{2}$$

Solution

As there are $$ 2 $$ negative numbers in the numerator and $$ 2 $$ in the denominator, the answer will be positive.

Canceling out the common factors and simplifying we get

$$ \dfrac { 5\times (-144)\times (-27) }{ -(15)\times 18 \times (-16) } =\dfrac{9 \times 27}{3 \times 18} =\dfrac{9}{2}$$
Question 8
1 / -0

The identity elements with respect to multiplication in integers is

A
$$1$$

B
$$-1$$

C
$$0$$

D
none

Solution

Any number when multiplied by $$1$$, results in the number itself.
Hence, $$1$$ is the identity element with respect to multiplication.
Question 9
1 / -0

$$(-12) \times (+21) =$$

A
$$-2412$$

B
$$-242$$

C
$$-252$$

D
$$+252$$

Solution

We know that the product of two integers with unlike signs is always negative.

We are given the two unlike integers, one with positive sign and one with negative sign that is $$-12$$ and $$+21$$ then the product of these integers is:

$$(-12)\times (+21)=-(12\times 21)=-252$$ which is a negative integer.

Hence, $$(-12)\times (+21)=-252$$.
Question 10
1 / -0

The temperature at the foot of a mountain is $$+5^{\circ}$$C. It fell down by $$10^{\circ}$$C at the top of the mountain. The temperature recorded on the top is:

A
$$+15^{\circ}$$C

B
$$-15^{\circ}$$C

C
$$+5^{\circ}$$C

D
$$-5^{\circ}$$C

Solution

It is given that the temperature at the foot of a mountain is $$+5^0$$C and it fell down by $$10^0$$C at the top of the mountain which can be represented as $$-10^0$$C.

Adding both to find the temperature recorded on the top as follows:

$$(+5)+(-10)=5-10=-5$$

Hence, the temperature recorded on the top is $$-5^0$$C.

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Re-Attempt Weekly Quiz Competition

Integers Test - 33

Result

Integers Test - 33

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SHARING IS CARING

Question 1

$$(-4) \div 16$$

$$-(16 \div 4)$$

$$16 \div(-4)$$

$$-4$$

Solution

Question 2

Closure

Commutative

Associativity

All of these

Solution

Question 3

$$5$$

$$-5$$

$$15$$

$$-19$$

Solution

Question 4

$$-250$$

$$(-25)\times 10$$

$$(-25)\times 6\times 4$$

$$(-25)\times 6+(-25)\times 4$$

Solution

Question 5

$$3300$$

$$-3300$$

$$3432$$

$$-3432$$

Solution

Question 6

$$0$$

$$-1$$

$$-10$$

None of these

Solution

Question 7

$$\dfrac {9}{4}$$

$$\dfrac {9}{8}$$

$$\dfrac {9}{2}$$

$$\dfrac {-9}{2}$$

Solution

Question 8

$$1$$

$$-1$$

$$0$$

none

Solution

Question 9

$$-2412$$

$$-242$$

$$-252$$

$$+252$$

Solution

Question 10

$$+15^{\circ}$$C

$$-15^{\circ}$$C

$$+5^{\circ}$$C

$$-5^{\circ}$$C

Solution

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