Integers Test

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Integers Test - 40

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following is not the additive inverse of a?

A
$$-(-a)$$

B
$$a \times(-1)$$

C
$$-a$$

D
$$a \div(-1)$$

Solution

Option (a) is correct.The additive inverse of a is a. Hence, $$-(-a)$$ is not correct.
Question 2
1 / -0

When the integers 10, 0, 5, 5, 7 are arranged in descending or ascending order, them find out which of the following integers always remains in the middle of the arrangement.

A
0

B
5

C
-7

D
-5

Solution

The given integers are 10, 0, 5,-5,-7
Descending order: 10, 5, 0,-5,-7
Ascending order: -7,-5, 0, 5, 10Therefore, the integer, which always remains in the middle of the arrangement, is zero (0).
Question 3
1 / -0

$$(-43) \times(-99)+43$$ is equal to

A
$$4300$$

B
$$- 4300$$

C
$$4257$$

D
$$- 4214$$

Solution

Option (a) is correct.
$$\begin{array}{l}\Rightarrow(-43) \times(-99)+43 \\=(-43 \times-99)+43 \\=4257+43\\=4300\end{array}$$
Question 4
1 / -0

$$[(-8) \times(-3)] \times(-4)$$ is not equal to

A
$$(-8) \times[(-3) \times(-4)]$$

B
$$[(-8) \times(-4)] \times(-3)$$

C
$$[(-3) \times(-\mathbf{8})] \times(-\mathbf{4})$$

D
$$(-8) \times(-3)-(-8) \times(-4)$$

Solution

Option (d) is correct.
$$[(-8) \times(-3)] \times(-4)=(-8) \times[(-3) \times(-4)]$$
$$\begin{array}{l}{[(-\mathbf{8}) \times(-\mathbf{3})] \times(-\mathbf{4})=[(-\mathbf{8}) \times(-\mathbf{4})] \times(-\mathbf{3})} \\{[(-\mathbf{8}) \times(-\mathbf{3})] \times(-\mathbf{4})=[(-\mathbf{3}) \times(-\mathbf{8})] \times(-\mathbf{4})}\end{array}$$
But,
$$[(-8) \times(-3)] \times(-4) \neq(-8) \times(-3)-(-8) \times(-4)$$
Therefore, option(d) is not correct
Question 5
1 / -0

Encircle the odd one of the following

A
$$(-\mathbf{4},\mathbf{1})$$

B
$$(-\mathbf{5},+\mathbf{2})$$

C
$$(-\mathbf{4},+\mathbf{1})$$

D
$$(-9,+7)$$

Solution

Option (d) is correct.
(a) $$-4+1=-3$$
(b) $$-5+2=-3$$
(c) $$-4+1=-3$$
(d) $$-9+7=-2$$

By the above calculation, we can see that option d gives -2 while other options give -3. Thus, option d is different from all others.
Question 6
1 / -0

Encircle the odd one of the following

A
(-3,3)

B
(-5,5)

C
(-6,1)

D
(-8,8)

Solution

Option (c) is correct.
(a) $$-3+3=0$$
(b) $$-5+5=0$$
(c) $$-6+1=-5$$
(d) $$-8+8=0$$

By the above calculation, we can see that option c gives $$-5$$ while other options give $$0$$. Thus, option $$c$$ is different from all others.
Question 7
1 / -0

Choose the odd one of the following

A
$$(-\mathbf{1}) \times(-\mathbf{1})$$

B
$$(-1) \times(-1) \times(-1)$$

C
$$(-\mathbf{1}) \times(-\mathbf{1}) \times(-\mathbf{1}) \times(-\mathbf{1})$$

D
$$(-1) \times(-1) \times(-1) \times(-1) \times(-1) \times(-1)$$

Solution

(a) $$(-1) \times(-1)=1$$
(b) $$(-1) \times(-1) \times(-1)=-1$$
(c) $$(-1) \times(-1) \times(-1) \times(-1)=1$$
(d) $$\begin{aligned} &(-1) \times(-1) \times(-1) \times(-1) \times(-1) \times(-1)=1\end{aligned}$$

By the above calculation, we can see that option $$(b)$$ gives $$-1$$ while other options give $$1.$$ Thus, option $$(b)$$ is different from all others.
Question 8
1 / -0

Which of the following is different from the others?

A
$$20+(-25)$$

B
$$(-37)-(-32)$$

C
$$(-\mathbf{5}) \times(-\mathbf{1})$$

D
$$(45) \div(-9)$$

Solution

Option (c) is correct.
$$(a) \Rightarrow 20+(-25)=20-25=-5$$
$$(b) \Rightarrow(-37)-(-32)=-37+32=-5$$
$$(c) \Rightarrow(-5) \times(-1)=5$$
$$(d) \Rightarrow(45) \div(-9)=-5$$

We can see here, 5 is a positive integer while others are negative integers.
Question 9
1 / -0

Encircle the odd one of the following

A
$$(-9) \times 5 \times 6 \times(-3)$$

B
$$9 \times(-5) \times 6 \times(-3)$$

C
$$(-9) \times(-5) \times(-6) \times 3$$

D
$$9 \times(-5) \times(-6) \times 3$$

Solution

Option (c) is correct.
(a) $$(-9) \times 5 \times 6 \times(-3)=810$$
(b) $$9 \times(-5) \times 6 \times(-3)=810$$
$$(c) $$ $$(-9) \times(-5) \times(-6) \times 3=-810$$
$$(d) $$ $$9 \times(-5) \times(-6) \times 3=810$$

By the above calculation, we can see that option c gives - 810 while other options give 810. Thus, option c is different from all others.
Question 10
1 / -0

Which of the following is not allowed in a given equation?

A
Adding the same number to both sides of the equation.

B
Subtracting the same number from both sides of the equation.

C
Multiplying both sides of the equation by same non-zero number.

D
Dividing both sides of the equation by the same number.

Solution

Option (d) is correct.
U can divide both sides by any "non zero" number, but you cannot divide by zero. The option is therefore wrong.

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Re-Attempt Weekly Quiz Competition

Integers Test - 40

Result

Integers Test - 40

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Question 1

$$-(-a)$$

$$a \times(-1)$$

$$-a$$

$$a \div(-1)$$

Solution

Question 2

0

5

-7

-5

Solution

Question 3

$$4300$$

$$- 4300$$

$$4257$$

$$- 4214$$

Solution

Question 4

$$(-8) \times[(-3) \times(-4)]$$

$$[(-8) \times(-4)] \times(-3)$$

$$[(-3) \times(-\mathbf{8})] \times(-\mathbf{4})$$

$$(-8) \times(-3)-(-8) \times(-4)$$

Solution

Question 5

$$(-\mathbf{4},\mathbf{1})$$

$$(-\mathbf{5},+\mathbf{2})$$

$$(-\mathbf{4},+\mathbf{1})$$

$$(-9,+7)$$

Solution

Question 6

(-3,3)

(-5,5)

(-6,1)

(-8,8)

Solution

Question 7

$$(-\mathbf{1}) \times(-\mathbf{1})$$

$$(-1) \times(-1) \times(-1)$$

$$(-\mathbf{1}) \times(-\mathbf{1}) \times(-\mathbf{1}) \times(-\mathbf{1})$$

$$(-1) \times(-1) \times(-1) \times(-1) \times(-1) \times(-1)$$

Solution

Question 8

$$20+(-25)$$

$$(-37)-(-32)$$

$$(-\mathbf{5}) \times(-\mathbf{1})$$

$$(45) \div(-9)$$

Solution

Question 9

$$(-9) \times 5 \times 6 \times(-3)$$

$$9 \times(-5) \times 6 \times(-3)$$

$$(-9) \times(-5) \times(-6) \times 3$$

$$9 \times(-5) \times(-6) \times 3$$

Solution

Question 10

Adding the same number to both sides of the equation.

Subtracting the same number from both sides of the equation.

Multiplying both sides of the equation by same non-zero number.

Dividing both sides of the equation by the same number.

Solution

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