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Perimeter and Area Test - 10

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Perimeter and Area Test - 10
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  • Question 1
    1 / -0
    Find the area of a ring whose outer and inner radii are $$19\ cm$$ and $$16\ cm$$ respectively.
    Solution
    Let us given $$R = 19 $$ $$cm $$ & $$r = 16$$ $$cm $$
    Area of outer circle $$=\pi{(19)}^2$$
                                     $$=\cfrac{22}{7}\times 361$$
    Area of inner circle $$=\pi{(16)}^2$$
                                     $$=\cfrac{22}{7}\times 256$$
    $$\therefore$$ area of the ring $$=\dfrac{22}{7}\times 361-\dfrac{22}{7}\times 256$$
                                  $$=\cfrac{22}{7}(361-256)$$
                                  $$=\cfrac{22}{7}(105)$$
                                  $$=330\ cm^2$$

  • Question 2
    1 / -0
    The circumference of a circular field is $$308 m$$. Find its radius in metres.
    Solution
    The circumference of a circular field is $$308m$$
    Therefore, $$2\pi r=308$$
    $$\Rightarrow r=\cfrac{308\times 7}{2\times 22}$$
    $$\Rightarrow r=49m$$
  • Question 3
    1 / -0
    The total boundary length of circle is called 
    Solution
    Boundary length of circle is called circumference 
  • Question 4
    1 / -0
    Find the missing length of the following figure.

    Solution
    Let unknown side of the figure is $$x$$
    Perimeter $$=$$ sum of all sides of figure
    $$23=4+5+8+x$$
    $$x=23-17=6\text{ cm}$$.
  • Question 5
    1 / -0
    Find the missing length of the figure given below.

    Solution
    Let unknown side is $$x$$ 
    Perimeter $$=$$ sum of length.
    $$20=6+4+8+x$$
    $$x=20-18=2\text{ cm}$$
  • Question 6
    1 / -0
    A circle is inscribed in a square as shown below. If the radius of the circle is $$4$$ cm, then the perimeter of the square is ______

    Solution
    From the fig it is clear that,
    Diameter of the circle $$=$$ side of the square
    So length of side of square  $$=2\times$$ $$4$$ cm 
                                                $$=8$$ cm
    $$\therefore$$ perimeter of the square  $$=8 + 8 + 8 + 8 $$
                                              $$= 32$$ cm
  • Question 7
    1 / -0
    Perimeter of a circle is called as__________
    Solution
    Perimeter of a circle is equal to its circumference i.e., $$P=2\pi r$$
  • Question 8
    1 / -0
    Perimeter of a circle is called as
    Solution
    Perimeter of a circle is called as circumference.
    The formula of circumference is  $$2\pi r$$
    Option B is correct.
  • Question 9
    1 / -0
    Perimeter of a circle is called its
    Solution
    Perimeter of a circle is called its circumference.
  • Question 10
    1 / -0
    The radius of a wheel is $$0.25 m$$. How many rounds will it take to complete the distance of $$11 km$$?
    Solution
    Distance covered in one round $$=$$ Circumference of wheel 
    $$\Rightarrow 2\pi r= 2 \times \cfrac{22}{7} \times 0.25 =\cfrac{11}{7}m$$
    $$ \displaystyle \therefore $$ Number of rounds to cover $$11 km  =\cfrac{\text {Total distance covered}}{\text {Distance covered in one  round}}=\cfrac{11\times\:1000}{\frac{11}{7}}=7000$$
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