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Exponents and Powers Test - 4

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Exponents and Powers Test - 4
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  • Question 1
    1 / -0

    The value of (30 − 20) × 52 is:

    Solution

    Anything raised to power 0 is 1.

    30 = 20 = 1

    (1-1) x 25 = 0

     

  • Question 2
    1 / -0

    {(3/4)−1 −(1/4)−1}−1 =?

    Solution

    {(3/4)−1 −(1/4)−1}−1 = {4/3−4}−1 = {−8/3}−1 = −3/8

     

  • Question 3
    1 / -0

    What is the value of 27 × 53 ?

    Solution

    Expand 27 × 5and find the product of the prime factors.
    2× 5= 2 × 2 × 2 × 2 × 2 × 2 × 2 × 5 × 5 × 5 = 128 × 125 = 16000

     

  • Question 4
    1 / -0

    {(1/3)−3 −(1/2)−3} ÷ (1/4)−3 =?

    Solution

    {(1/3)−3 −(1/2)−3} ÷ (1/4)−3 = {(3)3−(2)3} ÷ (4)={27−8}÷64 = 19/64

     

  • Question 5
    1 / -0

    If (3/2)× (3/2)a+5 = (3/2)8, then a =____.

    Solution

    (3/2)× (3/2)a+5 = (3/2)8 ⇒  (3/2)a+7 = (3/2)8
    On comparing, we get, a+7= 8 ⇒ a =1

     

  • Question 6
    1 / -0

    Express (−2)÷ m3 in the form (a/b).

    Solution

    am + bm = (a/b)m → (−2)+ m= (−2/m)3

     

  • Question 7
    1 / -0

    Find the value of 53 × 23 :

    Solution

    Notice that here the two terms 53 and 23 have different bases, but same exponents.

    53 × 23 = (5 × 5 × 5) × (2 × 2 × 2)

    = (5 × 2) × (5 × 2) × (5 × 2)

    = 103 = 1000

     

  • Question 8
    1 / -0

    The value of (33 × 23 × 50) is:

    Solution

    Expanding the terms

    33 = 27

    23 = 8

    50 = 1

    27 × 8 × 1 = 216

     

  • Question 9
    1 / -0

    The value of (23/25)× (−1/2)× 2× (3/4)is

    Solution

    (23/25)× (−1/2)× 2× (3/4)2 = 1 × (−1)× (2)−5 × 2× 3× (2)−4

    = −9/64

     

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