Data Handling Test

Result

Data Handling Test - 11

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Weekly Quiz Competition

Question 1
1 / -0

Find the arithmetic mean of integers from $$-5$$ to $$5$$

A
$$-1$$

B
$$0$$

C
$$1$$

D
None of these

Solution

Integers from $$-5$$ to $$+5$$ are $$= -5,-4,-3,-2,-1,0,1,2,3,4,5$$
sum of all these integers $$=0$$
so mean $$= 0$$
Question 2
1 / -0

Find the mean of:
$$3, 5, 3, 4, 2, 0, 7$$ and $$10$$

A
$$3.5$$

B
$$3.75$$

C
$$4$$

D
$$4.25$$

Solution

We need to find mean of $$3,5,3,4,2,0,7$$ and $$10$$.
Therefore, mean $$=\dfrac {3+5+3+4+2+0+7+10}{8}$$
$$=\dfrac {34}{8}=4.25$$
Question 3
1 / -0

Find the mean of integers from $$-4$$ to $$5$$

A
$$-1$$

B
$$0$$

C
$$0.5$$

D
$$1$$

Solution

integers from $$-4$$ to $$+5$$ are $$= -4,-3,-2,-1,0,1,2,3,4,5$$
sum of all these integers $$=5$$
total elements $$= 10$$
so mean $$= \dfrac{5}{10} = 0.5$$
Question 4
1 / -0

Find the mean of:
$$5, 15, 20, 8$$ and $$12$$.

A
$$12$$

B
$$11$$

C
$$10$$

D
$$9$$

Solution

The observations are: $$5, 15, 20, 8, 12$$
Mean $$= \cfrac{\text{Sum}}{\text{Number of observations}}$$
Mean $$= \cfrac{5 + 15 + 20 + 8 + 12}{5}$$
mean $$= \cfrac{60}{5} = 12$$
Question 5
1 / -0

Find the mode of:
Height ($$cm$$)
$$37$$
$$38$$
$$39$$
$$40$$
$$41$$
Number of plants $$46$$
$$89$$
$$93$$ $$90$$
$$153$$

A
$$38$$

B
$$39$$

C
$$40$$

D
$$41$$

Solution

mode $$=41$$ (highest frequency $$= 153$$)
Question 6
1 / -0

Find the mean of $$43, 51, 50, 57$$ and $$54$$

A
$$50$$

B
$$42.5$$

C
$$55$$

D
$$57$$

Solution

The observations are : $$43, 51, 50, 57$$ and $$54$$
mean $$= \cfrac{\text{Sum}}{\text{Count of numbers}}$$
mean $$= \cfrac{43 + 51 + 50 +57 +54}{5}$$
mean $$= \cfrac{255}{5}$$
mean $$= 51$$
Question 7
1 / -0

Mean of $$130,126,68,50,1$$ is

A
$$80$$

B
$$82$$

C
$$157$$

D
$$75$$

Solution

Required mean $$=\displaystyle\frac{130+126+68+50+1}{5} = \displaystyle\frac{375}{5} = 75$$
Question 8
1 / -0

The mean of first six natural numbers is

A
$$5$$

B
$$3.5$$

C
$$4$$

D
None of these

Solution

$$\textbf{Step -1: Find the sum of first six natural numbers.}$$

$$\text{The first six natural numbers are }1,2,3,4,5,6$$

$$\text{Sum of these observations}=1+2+3+4+5+6$$

$$=21$$

$$\textbf{Step -2: Find the mean of first six natural numbers.}$$

$$\text{Here, number of observations}=6$$

$$\mathbf{\because\text{Mean}=\dfrac{\text{Sum of observations}}{\text{Number of observations}}.}$$

$$\therefore\text{Mean of first six natural numbers}=\dfrac{21}{6}$$

$$=3.5$$

$$\textbf{Final Answer: Hence, the correct option is B.}$$
Question 9
1 / -0

The difference between the greatest and the least value of the observations is known as

A
M.D.

B
S.D.

C
Range

D
Variance

Solution

The difference between the greatest and the least value of the observations is defined as $$Range$$.
Question 10
1 / -0

The mean of $$994$$, $$996$$, $$998$$, $$1000$$ and $$1002$$ is

A
$$992$$

B
$$1004$$

C
$$998$$

D
$$999$$

Solution

Given observations: $$994, 996, 998, 1000, 1002$$
Mean $$=\dfrac{Sum}{Number \quad of \quad observations}$$

Mean $$=\dfrac{994 + 996 + 998 + 1000 + 1002}{5}$$

Mean $$=\dfrac{4990}{5}$$

Mean $$=998$$

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Re-Attempt Weekly Quiz Competition

Height ($$cm$$)	$$37$$	$$38$$	$$39$$	$$40$$	$$41$$
Number of plants	$$46$$	$$89$$	$$93$$	$$90$$	$$153$$

Data Handling Test - 11

Result

Data Handling Test - 11

Score

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Rank

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SHARING IS CARING

Question 1

$$-1$$

$$0$$

$$1$$

None of these

Solution

Question 2

$$3.5$$

$$3.75$$

$$4$$

$$4.25$$

Solution

Question 3

$$-1$$

$$0$$

$$0.5$$

$$1$$

Solution

Question 4

$$12$$

$$11$$

$$10$$

$$9$$

Solution

Question 5

$$38$$

$$39$$

$$40$$

$$41$$

Solution

Question 6

$$50$$

$$42.5$$

$$55$$

$$57$$

Solution

Question 7

$$80$$

$$82$$

$$157$$

$$75$$

Solution

Question 8

$$5$$

$$3.5$$

$$4$$

None of these

Solution

Question 9

M.D.

S.D.

Range

Variance

Solution

Question 10

$$992$$

$$1004$$

$$998$$

$$999$$

Solution

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