Data Handling Test

Result

Data Handling Test - 12

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Median of the observatios $$5$$, $$7$$, $$14$$, $$12$$, $$15$$, $$17$$, $$17$$, $$5$$, $$14$$, $$7$$, $$5$$ is

A
$$14$$

B
$$12$$

C
$$11.8$$

D
$$7$$

Solution

By arranging the given no's in increasing order, we get:
$$ 5,5,5,7,7,12,14,14,15,17,17 $$
Total terms $$= 11$$
since, the middle most term is $$ 6^{th} $$.
$$\therefore $$ value of median is $$12$$
$$\therefore $$ Option $$B$$ is correct.
Question 2
1 / -0

Find the mode of $$14$$, $$25$$, $$14$$, $$28$$, $$18$$, $$17$$, $$18$$, $$14$$, $$23$$, $$22$$, $$14$$, $$18$$.

A
$$14$$

B
$$25$$

C
$$28$$

D
$$18$$

Solution

Here, we arrange the data in the ascending order :- $$14,14,14,14,17,18,18,18,22,23,25,28$$
The value $$14$$ has maximum frequency.
Therefore, the mode of the data is $$14$$.
Question 3
1 / -0

The runs scored by Sachin in $$5$$ test matches are $$140$$, $$153$$, $$148$$, $$150$$ and $$154$$ respectively. Find his mean

A
$$150$$

B
$$149$$

C
$$148$$

D
$$147$$

Solution

Runs score by Sachin in $$5$$ test matches: $$140,153,148,150,154$$
Mean of runs $$= \cfrac{\text{Total runs}}{\text{Number of matches}}$$
Mean $$= \cfrac{140 + 153 + 148 + 150 + 154}{5}$$
Mean $$= \cfrac{745}{5}$$
Mean $$= 149$$
Question 4
1 / -0

Mean of a set of observations is the value which

A
occurs most frequently

B
divides observations into two equal parts

C
is a representative of whole group

D
is the sum of observation

Solution

Mean is the value which is the representative of the whole group. As, this takes into account all the values present in the group and averages them.
Question 5
1 / -0

Find the mean of $$43, 51, 50, 57$$ and $$54$$.

A
$$51$$

B
$$57$$

C
$$40$$

D
$$43$$

Solution

Mean of $$43, 51, 50, 57, 54$$
Mean $$= \cfrac{\text{Sum}}{\text{Number of observations}}$$
Mean $$= \cfrac{43 + 51 + 50 + 57 + 54}{5} = \cfrac{255}{5} = 51$$
Question 6
1 / -0

Find the mean of the following data: $$18, 33, 30, 21$$ and $$13$$.

A
$$18$$

B
$$23$$

C
$$25$$

D
$$15$$

Solution

Given set of data is $$18,33,30,21,13$$
Arranging the data in ascending order, we get $$13,18,21,30,33$$
No of terms(numbers) $$=n=5$$
Mean $$=\dfrac{\text{Sum of numbers}}{n}$$
$$=\dfrac{13+18+21+30+33}{5}=\dfrac{115}{5}=23$$
Thus, Mean of given data is $$23$$.
Hence, option B is correct.
Question 7
1 / -0

The heights of $$6$$ boys in a group are $$142$$ cm, $$154 $$ cm, $$146$$ cm, $$145$$ cm, $$151$$ cm and $$150$$ cm. Find the mean height per boy

A
$$122$$ cm

B
$$148$$ cm

C
$$156$$ cm

D
$$173$$ cm

Solution

Mean height $$=\cfrac{\text{Sum of the height of the all boys}}{\text{No. of boys}}$$
$$=\cfrac{142+154+146+145+151+150}{6}$$
$$=\cfrac{888}{6}=148$$ cm
Hence, the mean height is $$148$$ cm.
Question 8
1 / -0

Find the mean of the observations $$8, 12, 16, 22, 10$$ and $$4$$.

A
$$13$$

B
$$15$$

C
$$14$$

D
$$12$$

Solution

The given observations are: $$8, 12, 16, 10, 22, 4$$
Mean $$= \cfrac{\text{Sum}}{\text{Number of observations}}$$
Mean $$= \cfrac{8+ 12 + 16 + 10 + 22 + 4}{6} = \cfrac{72}{6} = 12$$
Question 9
1 / -0

Mode is

A
Most frequent value

B
Least frequent value

C
Middle most value

D
None of these

Solution

The value which occurs the maximum number of times in the dataset or which has the highest frequency is the mode of the dataset.
Question 10
1 / -0

Sachin scored $$80 $$ and $$120$$ runs respectively in the two innings of a cricket match. What would have been his average score in each innings?

A
$$80$$

B
$$120$$

C
$$200$$

D
$$100$$

Solution

$$\Rightarrow$$ Runs scored by Sachin in fist innings $$=80$$
$$\Rightarrow$$ Runs scored by Sachin in fist innings $$=120$$
$$\Rightarrow$$ Total runs scored in two innings by Sachin $$=80+120=200$$
$$\Rightarrow$$ Average scored of Sachin in each innings $$=\dfrac{200}{2}=100$$

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Data Handling Test - 12

Result

Data Handling Test - 12

Score

-

Rank

-

SHARING IS CARING

Question 1

$$14$$

$$12$$

$$11.8$$

$$7$$

Solution

Question 2

$$14$$

$$25$$

$$28$$

$$18$$

Solution

Question 3

$$150$$

$$149$$

$$148$$

$$147$$

Solution

Question 4

occurs most frequently

divides observations into two equal parts

is a representative of whole group

is the sum of observation

Solution

Question 5

$$51$$

$$57$$

$$40$$

$$43$$

Solution

Question 6

$$18$$

$$23$$

$$25$$

$$15$$

Solution

Question 7

$$122$$ cm

$$148$$ cm

$$156$$ cm

$$173$$ cm

Solution

Question 8

$$13$$

$$15$$

$$14$$

$$12$$

Solution

Question 9

Most frequent value

Least frequent value

Middle most value

None of these

Solution

Question 10

$$80$$

$$120$$

$$200$$

$$100$$

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.