Data Handling Test

Result

Data Handling Test - 14

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Weekly Quiz Competition

Question 1
1 / -0

Find the arithmetic mean of $$24 $$ and $$36.$$

A
26

B
28

C
30

D
32

Solution

Arithmetic mean of two quantity $$a,b$$ $$= \dfrac{a+b}{2}$$

$$AM $$ of $$24, 36 = \dfrac{24+36 }{2} = \dfrac{60}{2} = 30$$
Question 2
1 / -0

The average of eight numbers is $$38.4$$ and the average of seven of them is $$39.2$$. What is the eighth number?

A
$$0.8$$

B
$$32.8$$

C
$$34.8$$

D
$$33.8$$

Solution

Sum of eight numbers $$= 38.4 \times 8 = 307.2$$
$$\because $$ Total sum $$=$$ Average $$\times$$ Number of items
Sum of seven numbers $$=39.2 \times 7 = 274.4$$
$$\therefore$$ Eight number $$= 307.2 - 274.4 = 32.8$$
Question 3
1 / -0

A graph drawn using vertical bars is called

A
Bar graph

B
Line graph

C
Pictograph

D
Pie graph

Solution

Bar graph represents the data in the form of vertical bars.
Question 4
1 / -0

If the median of $$\displaystyle \frac{x}{5}$$ $$\displaystyle x$$ $$\displaystyle \frac{x}{4}$$ $$\displaystyle \frac{x}{2}$$ and $$\displaystyle \frac{x}{3}$$ $$\displaystyle \left ( where\, x> 0 \right )$$ is $$8$$ then the value of $$x$$ would be

A
$$24$$

B
$$32$$

C
$$8$$

D
$$16$$

Solution

Arranging in ascending order the values are
$$\displaystyle \frac{x}{5},\frac{x}{4},\frac{x}{3},\frac{x}{2},x $$
Middle value $$=\displaystyle \frac{x}{3}\Rightarrow \frac{x}{3}=8\Rightarrow x=24 $$
Question 5
1 / -0

The median of the following data $$46, 64, 87, 41, 58, 77, 35, 90, 55, 33, 92$$ is ,

A
$$87$$

B
$$77$$

C
$$58$$

D
$$60.2$$

Solution

Arrange the given data in ascending order.
We have, $$33, 35, 41, 46, 55, 58, 64, 77, 87, 90$$ and $$92.$$
The sixth entry is $$58.$$
Median is $$58.$$
Question 6
1 / -0

The arithmetic mean of $$12$$ and $$20$$ is :

A
$$12$$

B
$$14$$

C
$$16$$

D
$$18$$

Solution

The arithmetic mean of two numbers is their average.

So, the AM of $$12$$ and $$20$$ is $$ \dfrac { 12+ 20 }{ 2 }= 16$$
Question 7
1 / -0

If the arithmetic mean of $$6, 8, 5, 7, x$$ and $$4$$ is $$7,$$ then $$x$$ is

A
$$12$$

B
$$6$$

C
$$8$$

D
$$4$$

Solution

$$\textbf{Step - 1: Solving for x.}$$
$$\text{Observation given = }{6, 8, 5, 7, x, 4}$$
$$\text{Arithmetic mean = 7}$$
$$\text{Arithmetic mean = }\dfrac{\text{Sum of observations.}}{\text{Number of observations.}}$$
$$\Rightarrow \dfrac{6 + 8 + 5 + 7 + x + 4}{6} = 7$$
$$30 + x = 7 \times 6$$
$$x = 42 - 30$$
$$x = 12$$
$$\textbf{Hence, the value of x is 12. (Option A)}$$
Question 8
1 / -0

The average of $$2, 4, 6, 8, 10\ is $$

A
$$5$$

B
$$6$$

C
$$7$$

D
$$8$$

Solution

Average = $$\displaystyle \frac{2+4+6+8+10}{5}=6$$
Question 9
1 / -0

The average of the five odd numbers between $$18$$ and $$28$$ is

A
$$18$$

B
$$20$$

C
$$15$$

D
$$23$$

Solution

Given odd numbers between $$18$$ and $$28$$ are $$19,21,23,25,27$$

$$\text{Average} =\dfrac{19+21+23+25+27}{5} \\\ \ \ \ \ \ \ \ \ \ \ \ \ \ =\dfrac {115}{5}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ = 23$$
Question 10
1 / -0

The weights of 9 apples are 50,60,65,62,67,70,64,45,48 grams Their mean weight is

A
$$60.5\ gram$$

B
$$60\ gram$$

C
$$59\ gram$$

D
$$62\ gram$$

Solution

Mean =$$\dfrac{Total\ weight\ of\ 9\ apples}{Total\ no\ of\ apple}$$
$$\Rightarrow \dfrac{50+60+65+62+67+70+64+45+48}{9}$$
$$\Rightarrow \dfrac{531}{9}=59$$

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Re-Attempt Weekly Quiz Competition

Data Handling Test - 14

Result

Data Handling Test - 14

Score

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Rank

-

SHARING IS CARING

Question 1

26

28

30

32

Solution

Question 2

$$0.8$$

$$32.8$$

$$34.8$$

$$33.8$$

Solution

Question 3

Bar graph

Line graph

Pictograph

Pie graph

Solution

Question 4

$$24$$

$$32$$

$$8$$

$$16$$

Solution

Question 5

$$87$$

$$77$$

$$58$$

$$60.2$$

Solution

Question 6

$$12$$

$$14$$

$$16$$

$$18$$

Solution

Question 7

$$12$$

$$6$$

$$8$$

$$4$$

Solution

Question 8

$$5$$

$$6$$

$$7$$

$$8$$

Solution

Question 9

$$18$$

$$20$$

$$15$$

$$23$$

Solution

Question 10

$$60.5\ gram$$

$$60\ gram$$

$$59\ gram$$

$$62\ gram$$

Solution

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