Data Handling Test

Result

Data Handling Test - 18

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Weekly Quiz Competition

Question 1
1 / -0

The mean of $$56,15,48,49,52,57,30,51,42,50$$ is

A
45

B
50

C
55

D
None of these

Solution

Given data is $$56,15,48,49,52,57,30,51,42,50$$
No .of observations $$10$$
Sum of observations is $$56+15+48+49+52+57+30+51+42+50=450$$
Mean of the data is $$\dfrac{450}{10}=45$$
Question 2
1 / -0

Find the mean of $$35,34,25,52,27,23,24,36$$

A
32

B
28

C
24

D
30

Solution

Given data $$35,34,25,52,27,23,24,36$$
No .of observations $$8$$
Sum of observations $$35+34+25+52+27+23+24+36=256$$
Mean is $$\frac{256}{8}=32$$
Question 3
1 / -0

Find the mean of $$36,40,32,48,44$$

A
40

B
45

C
50

D
35

Solution

No .of observations $$5$$
Sum of observations $$36+40+32+48+44=200$$
Mean $$\dfrac{200}{5}=40$$
Question 4
1 / -0

The mean of $$33,53,32,35,47$$ is

A
$$40$$

B
$$56$$

C
$$55$$

D
$$6^{6}-6!$$

Solution

Given observations $$33,53,32,35,47$$
no. of observations is $$5$$
Sum of observations is $$33+53+32+35+47=200$$
Mean is $$\dfrac{200}{5}=40$$
Question 5
1 / -0

Find the mean of $$22,16,19,12,26,32,87,58$$

A
34

B
32

C
43

D
none of these

Solution

given observations $$22,16,19,12,26,32,87,58$$
No .of observations $$8$$
Sum f observations $$22+16+19+12+26+32+87+58=272$$
Mean is given as $$\dfrac{272}8=34$$
Question 6
1 / -0

Find the mean of $$16,29,60,18,27$$

A
30

B
40

C
50

D
10

Solution

The given data is $$16,29,60,18,27$$
The sum of observations is $$16+29+60+18+27=150$$
The mean is given as $$\dfrac{150}{5}=30$$
Question 7
1 / -0

Find the mean of $$31,45,84,23,67$$

A
48

B
50

C
52

D
None.

Solution

Given data $$31,45,84,23,67$$
The sum of observations $$31+45+84+23+67=240$$
The mean $$\dfrac {240}{5}=48$$
Question 8
1 / -0

The mean of $$6,8,10,12,14,16,18$$

A
$$12$$

B
$$10$$

C
$$9$$

D
$$8$$

Solution

Given data $$6,8,10,12,14,16,18$$
The sum of observations is $$6+8+10+12+14+16+18=84$$

Mean $$= \dfrac{\text{Sum of given observations}}{\text{Total number of observations}}$$

Total number of observations = 7
Mean = $$\dfrac {84}7=12$$
Question 9
1 / -0

The mean of $$25,37,84$$ is

A
$$25$$

B
$$37$$

C
$$84$$

D
None.

Solution

Given observations $$25,37,84$$
No .of observations $$3$$
The mean of observation $$\dfrac{25+37+84}{3}=\dfrac {146}3=48.6$$
Question 10
1 / -0

Observe the adjoining bar graph, showing the number of one-day international matches played by cricket teams of different countries. Choose the correct answer from the given four options:
How many matches did South Africa play?

A
$$16$$

B
$$18$$

C
$$20$$

D
$$24$$

Solution

The given bar graph represents the number of matches played by cricket teams of different country.
We can prepare frequency table from given bar graph as follows:
Country No. of matches
India $$30$$
Pakistan $$24$$
West Indies $$20$$
England $$28$$
South Africa $$18$$
Australia $$32$$
Sri Lanka $$24$$
Clearly, the number of matches played by South Africa is $$18$$.
Hence, option $$B$$ is correct.

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Re-Attempt Weekly Quiz Competition

Data Handling Test - 18

Result

Data Handling Test - 18

Score

-

Rank

-

SHARING IS CARING

Question 1

45

50

55

None of these

Solution

Question 2

32

28

24

30

Solution

Question 3

40

45

50

35

Solution

Question 4

$$40$$

$$56$$

$$55$$

$$6^{6}-6!$$

Solution

Question 5

34

32

43

none of these

Solution

Question 6

30

40

50

10

Solution

Question 7

48

50

52

None.

Solution

Question 8

$$12$$

$$10$$

$$9$$

$$8$$

Solution

Question 9

$$25$$

$$37$$

$$84$$

None.

Solution

Question 10

$$16$$

$$18$$

$$20$$

$$24$$

Solution

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