Data Handling Test

Result

Data Handling Test - 22

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Weekly Quiz Competition

Question 1
1 / -0

The average of first $$4$$ prime numbers is?

A
$$4$$

B
$$4.25$$

C
$$5$$

D
$$6.25$$

Solution

Average is the sum of the data values divided by the total values.
The first $$4$$ prime numbers are $$2,3,5,7$$

Therefore, average of first $$4$$ prime numbers $$=\dfrac{2+3+5+7}{4}=\dfrac{17}{4}=4.25$$
Question 2
1 / -0

The weights of 9 apples are 50, 60, 65, 62, 67, 70, 64, 45, 48 grams. Their mean weight is

A
60.5 gram

B
60 gram

C
59 gram

D
62 gram

Solution

Given weights of 9 apples are 50, 60, 65, 62, 67, 70, 64, 45, 48 grams.

Then total weight of 9 apples =50+60+65+62+67+70+64+45+48=531
Then mean=$$\frac{539}{9}$$=59
Question 3
1 / -0

The sum of five numbers is $$555$$. The average of first two numbers is $$75$$ and the third number is $$115$$. What is the average of the last two numbers?

A
$$145$$

B
$$290$$

C
$$265$$

D
$$150$$

Solution

Let the five numbers be $$A, B, C, D, E$$
Given, $$A + B + C + D + E =555$$
$$\displaystyle \frac{A+B}{2} = 75 \Rightarrow A + B = 150 $$ and $$C = 115$$
$$\therefore 150 + 115 + D + E = 555$$
$$\Rightarrow D + E = 555 - 265 = 290$$
$$\therefore$$ Required Average $$= \displaystyle \frac{D + E}{2} = \frac{290}{2} = 145$$
Question 4
1 / -0

Which of the following is correct for the given data $$55, 38, 69, 24, 89$$?

A
$$median=mode$$

B
$$mean=mode$$

C
$$mean=median$$

D
None of these

Solution

$$24, 38, 55, 69, 89$$

$$Mean = \dfrac{sum\ of \ all \ the\ terms}{total\ number\ of\ terms} $$

$$Mean = \dfrac{24+38+55+69+89}{5}$$

$$Mean=\dfrac {275}{5}=55$$
if n (total number of terms ) is odd then the middle term when the data is arranged in ascending order is median
Arranging the data in ascending order, we get :
$$24, 38, 55, 69, 89$$
$$Median=55$$
Therefore, for the given data,$$Mean=median$$
Question 5
1 / -0

Find the mode of 0,0,2,2,3,3,3,4,5,5,5,5,6,6,7,8

A
8

B
0

C
2

D
5

Solution

$$Number$$ $$Frequency$$
0 2
2 2
3 3
4 1
5 4
6 2
7 1
8 1

Frequency of 5 is maximum. Hence 5 is the mode.
Question 6
1 / -0

The average maximum temperature for 7 days from the 12th September to 18th September is $$35^\circ C$$ and that for 7 days from 13th to 19th September is $$34^\circ C$$. From this we can conclude that

A
Maximum temperature on 19th is $$1^\circ C$$ less than that for 12th September

B
Maximum temperature on 12th is $$1^\circ C$$ less than that for 19th September

C
Maximum temperature on 19th is $$7^\circ C$$ less than that for 12th September

D
None of the above

Solution

The average maximum temp from 12th sept to 18th sept is 35 and The average maximum temp from 13th sept to 19th sept is 34
Then total temp from 12th sept to 18th sept =35$$\times$$7=245
And total temp from 13th sept to 19th sept =34$$\times$$7=238
Then diff=245-238=7
So Maximum temperature on 12th is7 $$^{0}$$ less than that for 19th September
7
77
Question 7
1 / -0

The average of the four even numbers between $$31$$ and $$39$$ is

A
$$35$$

B
$$21$$

C
$$20$$

D
$$19$$

Solution

Average is the sum of the data values divided by the total values.
The $$4$$ even numbers between $$31$$ and $$39$$ are $$32,34,36,38$$

Therefore, average of even numbers between $$31$$ and $$39$$ $$=\dfrac{32+34+36+38}{4}=\dfrac{140}{4}=35$$
Question 8
1 / -0

Given above is a bar graph showing the heights of six mountain peaks. Read the above diagram and answer the following:
Write the ratio of the heights of highest peak and the lowest peak.

A
$$22 : 15$$

B
$$15 : 22$$

C
$$20 : 13$$

D
$$13 : 22$$

Solution

From the above bar graph,
Height of highest peak $$= 8800\ m$$
Height of lowest peak $$= 6000\ m$$

Hence the required ratio will be,
Ratio $$=8800 : 6000$$
$$ = 22 :15$$

Hence, option $$A$$ is correct.
Question 9
1 / -0

The arithinetic mean of $$5, 6, 8, 9, 12, 13, 17$$ is

A
$$20$$

B
$$15$$

C
$$10$$

D
$$25$$

Solution

Mean $$ = \dfrac { \text{Sum of observations}}{\text{Total number of observations}} = \dfrac {5 + 6 + 8 + 9 + 12 + 13 + 17}{7} = \dfrac {70}{7} = 10 $$
Question 10
1 / -0

What are the number of outcomes of a game of cricket?

A
$$2$$

B
$$3$$

C
$$1$$

D
None of these

Solution

Total outcomes: $$3$$
1. Win or
2. Loose or
3. Tie

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Data Handling Test - 22

Result

Data Handling Test - 22

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SHARING IS CARING

Question 1

$$4$$

$$4.25$$

$$5$$

$$6.25$$

Solution

Question 2

60.5 gram

60 gram

59 gram

62 gram

Solution

Question 3

$$145$$

$$290$$

$$265$$

$$150$$

Solution

Question 4

$$median=mode$$

$$mean=mode$$

$$mean=median$$

None of these

Solution

Question 5

8

0

2

5

Solution

Question 6

Maximum temperature on 19th is $$1^\circ C$$ less than that for 12th September

Maximum temperature on 12th is $$1^\circ C$$ less than that for 19th September

Maximum temperature on 19th is $$7^\circ C$$ less than that for 12th September

None of the above

Solution

Question 7

$$35$$

$$21$$

$$20$$

$$19$$

Solution

Question 8

$$22 : 15$$

$$15 : 22$$

$$20 : 13$$

$$13 : 22$$

Solution

Question 9

$$20$$

$$15$$

$$10$$

$$25$$

Solution

Question 10

$$2$$

$$3$$

$$1$$

None of these

Solution

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