Data Handling Test

Result

Data Handling Test - 28

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Weekly Quiz Competition

Question 1
1 / -0

Four alternative options are given for each of the following statement . Select the correct option .
The mean of first three multiples of $$ 5 $$ is

A
$$ 5 $$

B
$$ 10 $$

C
$$ 15 $$

D
$$ 30 $$
Question 2
1 / -0

Marks obtain by five students in math are $$20, 25, 15, 35 $$ and $$ 30 $$ its range will be :

A
$$15$$

B
$$20$$

C
$$25$$

D
$$30$$

Solution

Range = Maximum value - minimum value $$ = 35 - 15 = 20 $$
Thus (B) is correct
Question 3
1 / -0

A student got 85, 87 and 83 marks in Mathematics, Physics and Chemistry respectively. Mean of obtained marks.

A
86

B
84

C
85

D
85.5

Solution

Given marks: $$85,\ 87,\ 83$$

Mean of marks $$= \dfrac{\mathrm{Sum\ of\ marks}}{\mathrm{No.\ of\ subjects}}$$

$$= \dfrac{85+87+83}{3} $$

$$= \dfrac{255}{3}$$

$$ = 85$$
Question 4
1 / -0

53, 75, 42, 70 are marks obtained by 4 students is statistics. Arithmetic mean of their marks is:

A
42

B
64

C
60

D
56

Solution

Given marks = 53, 75, 42, 70
Arithmetic mean $$= \frac{Sum\ of\ observations}{No.\ of\ observations}$$
$$= \frac{53+75+42+70}{4}$$
$$= \frac{240}{4} = 60$$
Question 5
1 / -0

The average of statistical data is called :

A
Arithmetic mean

B
Median

C
Mode

D
Frequency

Solution

The average of statistical data is called $$Mean$$ or $$Arithmatic\ mean$$

Hence, $$Op-A$$ is correct.
Question 6
1 / -0

Number of students in a school according to their age are as follows :
Age (in yrs.) No. of students
8 15
9 25
10 40
11 36
12 41
13 37
14 20
15 13
16 5
17 3
Their mode is

A
41

B
12

C
3

D
17

Solution

From above table it is clear that frequency 41 is maximum and its mavimum and its corresponding age group of 12 . So its mode will be 12.
Thus (B) is correct.
Question 7
1 / -0

The mode of the data$$4, 3, 4, 5, 4, 2, 4, 1$$ will be :

A
$$1$$

B
$$2$$

C
$$5$$

D
$$4$$

Solution

Arranging the numbers with the same values together, we get
$$1,2,3,4,4,4,4,5$$
Mode of this data is $$4$$ because it occurs more frequently than other observations.
Question 8
1 / -0

The mean of $$15, 0, 10, 5$$ will be :

A
$$15$$

B
$$10$$

C
$$5$$

D
$$7.5$$

Solution

The given number are $$15,0,10,5$$
The mean of a set of numbers is the sum divided by the number of terms.
Then, mean $$=\dfrac{15+0+10+5}{4}=\dfrac{30}{4}\\=7.5$$
Question 9
1 / -0

Range of the data $$6, 1, 2, 3, 9, 8, 3, 4, 8, 2, 3$$ is :

A
$$4$$

B
$$8$$

C
$$7$$

D
$$6$$

Solution

To find the range, first we need to order the data from least to greatest. Then we have to subtract the smallest value from the largest value in the set.

1,2,2,3,3,3,4,6,8,8,9

Then, 9-1 = 8
Question 10
1 / -0

The range is defined as :

A
the product of lower limit and upper limit

B
the average of the lowest and highest frequency

C
the difference of maximum and minimum values from the data

D
None of the above

Solution

The range of a set of data is the difference between the highest and lowest values in the set. To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest value in the set.

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Re-Attempt Weekly Quiz Competition

Age (in yrs.)	No. of students
8	15
9	25
10	40
11	36
12	41
13	37
14	20
15	13
16	5
17	3

Data Handling Test - 28

Result

Data Handling Test - 28

Score

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Rank

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SHARING IS CARING

Question 1

$$ 5 $$

$$ 10 $$

$$ 15 $$

$$ 30 $$

Question 2

$$15$$

$$20$$

$$25$$

$$30$$

Solution

Question 3

86

84

85

85.5

Solution

Question 4

42

64

60

56

Solution

Question 5

Arithmetic mean

Median

Mode

Frequency

Solution

Question 6

41

12

3

17

Solution

Question 7

$$1$$

$$2$$

$$5$$

$$4$$

Solution

Question 8

$$15$$

$$10$$

$$5$$

$$7.5$$

Solution

Question 9

$$4$$

$$8$$

$$7$$

$$6$$

Solution

Question 10

the product of lower limit and upper limit

the average of the lowest and highest frequency

the difference of maximum and minimum values from the data

None of the above

Solution

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