Simple Equations Test

Result

Simple Equations Test - 14

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Weekly Quiz Competition

Question 1
1 / -0

$$\text{If } 6x=12, \text{ then } x \text{ is}$$

A
$$12$$

B
$$2$$

C
$$72$$

D
$$6$$

Solution

Given, $$6x =12$$
Dividing both sides by $$6$$, we get:
$$\dfrac {6x}{6} = \cfrac { 12 }{ 6 } $$
$$\therefore \ x =2$$
Hence, option B is correct.
Question 2
1 / -0

Solve the following equation: $$x-2 = 7$$

A
$$7$$

B
$$2$$

C
$$9$$

D
$$11$$

Solution

Given, $$x-2=7$$
Add $$2$$ on both the sides, we get
$$x-2+2=7+2$$
$$\Rightarrow x=9$$
Hence, option C is correct.
Question 3
1 / -0

When $$6$$ is subtracted from four times a number, the result is $$54$$. What is the number?

A
$$60$$

B
$$30$$

C
$$15$$

D
$$10$$

Solution

Let the number be $$x$$.
Then, $$4x-6=54$$
Add 6 on both side
$$\Rightarrow \displaystyle 4x-6+6=54+6=>4x=60$$
Divide throughout by 4
$$\Rightarrow x=\dfrac{60}{4}=15$$
Hence, the required number is $$15$$.
Question 4
1 / -0

The solution of the equation $$7+3(x+5)=31$$ is

A
$$4$$

B
$$3$$

C
$$0$$

D
$$2$$

Solution

Given, $$7+3(x+5)=31$$
$$\Rightarrow 7+3x+15=31$$
$$\Rightarrow 22+3x=31$$
$$\Rightarrow \displaystyle 3x=31-22=9$$
$$\Rightarrow x=\dfrac{9}{3}=3$$.
Hence, required solution is $$x=3$$.
Question 5
1 / -0

Solve the following equation: $$6 = z+2$$

A
$$4$$

B
$$2$$

C
$$6$$

D
$$8$$

Solution

Given, $$6=z+2$$
Subtract $$2$$ on both the sides,
$$6-2=z+2-2$$
$$\Rightarrow z=4$$
Hence, option A is correct.
Question 6
1 / -0

Solve for $$x$$: $$3x+9=33$$

A
$$8$$

B
$$3$$

C
$$2$$

D
$$5$$

Solution

Given, $$3x+9=33$$
Subract 9 on both side
$$\Rightarrow 3x+9-9=33-9$$
$$\Rightarrow \displaystyle 3x=24$$
On dividing throughout by $$3$$, we get
$$\Rightarrow x=\dfrac{24}{3}=8$$
Hence, required solution is $$x=8$$.
Question 7
1 / -0

Solve the following equation: $$y+3 = 10$$

A
$$3$$

B
$$7$$

C
$$10$$

D
$$13$$

Solution

Given, $$y+3=10$$
Subtracting $$3$$ on both the sides, we get:
$$y+3-3=10-3$$
$$\Rightarrow y=7$$

Hence, option B is correct.
Question 8
1 / -0

If $$\dfrac{2x}{3}= 18$$, then $$x $$ is equal to

A
$$36$$

B
$$54$$

C
$$32$$

D
$$27$$

Solution

Given, $$\cfrac { 2x }{ 3 } =18$$
Multiply $$3$$ on both the sides, we get
$$2x = 18\times 3$$
$$\Rightarrow 2x= 54$$
Divide both side by 2
$$\Rightarrow x =27$$
Question 9
1 / -0

If $$\cfrac{t}{5} = 10$$, then $$t$$ is equal to

A
$$25$$

B
$$10$$

C
$$50$$

D
$$100$$

Solution

Given, $$ \dfrac { t }{ 5 } =10$$
To eliminate $$5$$ from the denominator, we multiply both sides by $$5$$
So, $$5 \times \dfrac {t}{5}=10\times 5$$
$$\Rightarrow t=50$$
Question 10
1 / -0

If $$7x-9 = 16$$, then $$x$$ is equal to:

A
$$x = \dfrac{16}{2}$$

B
$$x = \dfrac{7}{7}$$

C
$$x = \dfrac{25}{7}$$

D
$$x = \dfrac{2}{16}$$

Solution

Given, $$7x - 9 = 16$$
Add $$9$$ on both the sides, we get
$$7x-9+9=16+9$$
$$\therefore 7x =25$$
Divide $$7$$ on both the sides,
$$\therefore x = \dfrac { 25 }{ 7 } $$
Therefore, C is the correct answer.

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Re-Attempt Weekly Quiz Competition

Simple Equations Test - 14

Result

Simple Equations Test - 14

Score

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Rank

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SHARING IS CARING

Question 1

$$12$$

$$2$$

$$72$$

$$6$$

Solution

Question 2

$$7$$

$$2$$

$$9$$

$$11$$

Solution

Question 3

$$60$$

$$30$$

$$15$$

$$10$$

Solution

Question 4

$$4$$

$$3$$

$$0$$

$$2$$

Solution

Question 5

$$4$$

$$2$$

$$6$$

$$8$$

Solution

Question 6

$$8$$

$$3$$

$$2$$

$$5$$

Solution

Question 7

$$3$$

$$7$$

$$10$$

$$13$$

Solution

Question 8

$$36$$

$$54$$

$$32$$

$$27$$

Solution

Question 9

$$25$$

$$10$$

$$50$$

$$100$$

Solution

Question 10

$$x = \dfrac{16}{2}$$

$$x = \dfrac{7}{7}$$

$$x = \dfrac{25}{7}$$

$$x = \dfrac{2}{16}$$

Solution

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