Simple Equations Test

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Simple Equations Test - 15

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Weekly Quiz Competition

Question 1
1 / -0

Find the value of $$x$$: $$x-7=-8$$

A
$$1$$

B
$$-1$$

C
$$0$$

D
None of the above

Solution

$$ x-7=-8$$
Add $$7$$ to both sides,
$$\Longrightarrow x-7+7=-8+7$$
$$\Longrightarrow x=-8+7$$
$$\Longrightarrow x=-1$$
Hence, answer is option $$B$$.
Question 2
1 / -0

The mean of $$x, x+3, x+ 6, x+9$$ and $$x+12$$ is

A
$$x+6$$

B
$$x+3$$

C
$$x+9$$

D
$$x+12$$

Solution

By definition,
Average$$\:\displaystyle =\frac{x+\left ( x+3 \right )+\left ( x+6 \right )+\left ( x+9 \right )+\left ( x+12 \right )}{5}$$
$$\displaystyle =\frac{5x+30}{5}=x+6$$
Question 3
1 / -0

The arithmetic mean of 6,10, x and 12 is 8 The value of x is

A
$$3$$

B
$$4$$

C
$$5$$

D
$$6$$

Solution

Arithmetic Mean $$=\cfrac{{Sum \; of\; the\; terms}}{{Total\; number\; of\; terms}}$$
$$\Rightarrow 8=\dfrac{6+10+x+12}{4}$$
$$\Rightarrow 32=6+10+x+12$$
$$\Rightarrow x=32-28$$
$$\Rightarrow x=4$$
Question 4
1 / -0

Sunita's mother is 36 years old. She is 3 years older than 3 times sunita's age. What is sunita's age?

A
6

B
7

C
8

D
11

E
14

Solution

We do not know sunita’s age.
Let us take it to be $$y$$ years. .
Sunita’s mother’s age is 3years older than $$3y$$;
It is also given that Sunita’s mother is 36 years old.
Therefore, $$3y + 3 = 36$$
Subract $$3$$ from both side
$$3y+3-3=36-3$$
$$3y=33$$
Divide both side by 3
$$y=11$$
Question 5
1 / -0

The method of finding solution by trying out various values for the variable is called

A
Rrror method

B
Trial and error method

C
Testing method

D
Checking method

Solution

The required method is called "Trial and error method"
Question 6
1 / -0

Frame the statement into an equation:
Adding $$16$$ to $$3$$ times $$x $$ is $$39$$.

A
$$\displaystyle 3x-16=39$$

B
$$\displaystyle 3x+16=-39$$

C
$$\displaystyle -3x+16=39$$

D
$$\displaystyle 3x+16=39$$

Solution

$$3 \times x=3x$$

As per the given condition,
Adding $$16$$ to $$3x$$ results in $$16+3x=39$$

So, option $$D$$ is correct.
Question 7
1 / -0

Algebraic expression for the statement: $$6$$ times $$a$$ taken away from $$40$$

A
$$6a - 40$$

B
$$40a - 6$$

C
$$40 - 6a$$

D
$$0$$

Solution

Given, $$6$$ times $$a$$ takes away from $$40$$.
Required algebraic equation is given by,
$$40-6\times a=40-6a$$
Question 8
1 / -0

Convert the statement into an equation : Adding $$14$$ to $$9$$ times $$y$$ is $$89$$.

A
$$14y+9=89$$

B
$$14+9y=89$$

C
$$14-9y=-89$$

D
$$14+y=89$$

Solution

According to the question,
$$9$$ times $$y$$ means $$9 \times y = 9y$$.

Adding $$14$$ to it means $$9y+14$$.

$$\therefore$$ the equation is $$9y+14=89$$.
Question 9
1 / -0

Which of the sign should always be there in an equation?

A
$$=$$

B
$$\displaystyle \neq $$

C
$$\displaystyle >$$

D
$$\displaystyle <$$

Solution

An equation is a mathematical statement that two things are equal. It consists of two expressions, one on each side of an 'equals' sign. For example $$x=y$$ is an equation where two expressions $$x$$ and $$y$$ are equal.

Hence, $$=$$ sign should always be there in an equation.
Question 10
1 / -0

Sumeet guessed a number $$x$$ and then he added $$30$$ to it. Give the expression for double of it.

A
$$2(x+30)$$

B
$$\dfrac{1}{2(x+30)}$$

C
$$2x+30$$

D
$$x+60$$

Solution

According to the question,
The expression is $$x+30$$.
$$\therefore$$ double of it will be $$ 2(x+30$$).

So. option $$A$$ is correct.

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Re-Attempt Weekly Quiz Competition

Simple Equations Test - 15

Result

Simple Equations Test - 15

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SHARING IS CARING

Question 1

$$1$$

$$-1$$

$$0$$

None of the above

Solution

Question 2

$$x+6$$

$$x+3$$

$$x+9$$

$$x+12$$

Solution

Question 3

$$3$$

$$4$$

$$5$$

$$6$$

Solution

Question 4

6

7

8

11

14

Solution

Question 5

Rrror method

Trial and error method

Testing method

Checking method

Solution

Question 6

$$\displaystyle 3x-16=39$$

$$\displaystyle 3x+16=-39$$

$$\displaystyle -3x+16=39$$

$$\displaystyle 3x+16=39$$

Solution

Question 7

$$6a - 40$$

$$40a - 6$$

$$40 - 6a$$

$$0$$

Solution

Question 8

$$14y+9=89$$

$$14+9y=89$$

$$14-9y=-89$$

$$14+y=89$$

Solution

Question 9

$$=$$

$$\displaystyle \neq $$

$$\displaystyle >$$

$$\displaystyle <$$

Solution

Question 10

$$2(x+30)$$

$$\dfrac{1}{2(x+30)}$$

$$2x+30$$

$$x+60$$

Solution

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