Simple Equations Test

Result

Simple Equations Test - 9

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Weekly Quiz Competition

Question 1
1 / -0

Given A=P(1+rt),what is the value of 'r' when A=27, P=18 and t=5 ?

A
1/2

B
1/5

C
27/5

D
1/10

Solution

A=P(1+rt)⇒27=18(1+5r)⇒

r=27−18/18×1/5=1/2×1/5=1/10
Question 2
1 / -0

A person travelled 5/8thof the distance by train, 1/4th by bus and the remaining 15 km by boat. Find the total distance travelled by him.

A
90km

B
120km

C
150km

D
180km

Solution

Let the total distance be x km. ∴x−(5x/8+x/4)=15
(Given) ⇒x=Rs.1200
Question 3
1 / -0

5 less than thrice a number and add 7. The result is 14. The number is _____.

A
5

B
4

C
6

D
2

Solution

Let the number be x. According to question,

(3x−5)+7=14⇒

3x+2=14⇒3x=14−2⇒3x=12⇒x=12/3=4
Question 4
1 / -0

If 0.2(2x−1)−0.5(3x−1)=0.4,what is the value of x'?

A
1/11

B
-1/11

C
3/11

D
-3/11

Solution

0.2(2x−1)−0.5(3x−1)=0.4 ⇒ x=−1/11
Question 5
1 / -0

If two supplementary angles differ by 44^o, then one of the angles is ____.

A
102^o

B
65^o

C
112^o

D
72^o

Solution

Let first angle be x. Then, other angle will be

(44^o+x)

Now,

x+(44^o+x)=180^o⇒2x=136^o⇒x=68^o∴

First angle

=68^o

and second angle
Question 6
1 / -0

Form an equation of the form ax+b=c,where a, b and c are constants, such that the solution of the equation is x = 4.

A
2x+5=15

B
7x+2=10

C
5x+4=16

D
3x+4=16

Solution

(a) 2x+5=15⇒2x=10⇒x=5(b)
7x+2=10⇒7x=8⇒x=8/7(c)
5x+4=16⇒5x=12⇒x=12/5(d)
3x+4=16⇒3x=12⇒x=4

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Re-Attempt Weekly Quiz Competition

Simple Equations Test - 9

Result

Simple Equations Test - 9

Score

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Rank

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SHARING IS CARING

Question 1

1/2

1/5

27/5

1/10

Solution

Question 2

90km

120km

150km

180km

Solution

Question 3

5

4

6

2

Solution

Question 4

1/11

-1/11

3/11

-3/11

Solution

Question 5

102o

65o

112o

72o

Solution

Question 6

2x+5=15

7x+2=10

5x+4=16

3x+4=16

Solution

User

Question Analysis

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102^o

65^o

112^o

72^o