Mensuration Test

Result

Mensuration Test - 14

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

2(lb + bh + hl) is formula of---

A
Area of a cuboid

B
Area of a cube

C
Volume of a cuboid

D
None of these

Solution

The correct option is A.
Question 2
1 / -0

The number of surface areas in right circular cylinder is

A
$$1$$

B
$$2$$

C
$$3$$

D
$$4$$

Solution

As shown in figure of right circular cylinder, we have $$3$$ Surface areas they are :
Top Circular base area$$= \pi r^2$$
Lateral Surface area $$=2 \pi r$$
Bottom Circular base area $$=\pi r^2$$
hence, option $$C$$ is correct.
Question 3
1 / -0

A solid in the form of a cuboid is 4 cm x 3 cm x 2 cm. Its volume will be
(Note: cu cm $$=cm^3$$)

A
20 cu cm

B
22 cu cm

C
28 cu cm

D
24 cu cm

Solution

Volume of the cuboid =$$l$$ x$$ b$$ x$$ h$$ =$$4$$ x$$ 3$$ x$$ 2$$
$$ =24$$ cu cm
Question 4
1 / -0

$$\displaystyle \frac{1}{2}$$ (sum of parallel sides) $$\times$$ altitude is

A
Formula of area of trapezium

B
Formula of perimeter of rectangle

C
Formula of the rhombus

D
Formula of area of square

Solution

Area of trapezium $$= \dfrac{1}{2}\times $$(Sum of parallel sides)$$\times $$ (altitude)
Question 5
1 / -0

Volume of a suitcase with clothes in it is ................... the volume of empty suitcase. (Both suitcases are of same size)

A
more than

B
less than

C
equal to

D
none of these

Solution

Whether the volume of the suitcase is occupied or not the volume will remain the same. So the volume of the same suitcase whether it haves clothes in it or not will remain equal.
So option C is the correct answer.
Question 6
1 / -0

Volume of a cuboid with $$x$$ as length, $$y$$ as breadth and $$z$$ as height is

A
$$\displaystyle \frac{xy}{z}$$

B
$$xyz$$

C
$$x + y + z$$

D
$$x - (y + z)$$

Solution

$$\Rightarrow$$ Length of a cuboid $$(l)=x$$

$$\Rightarrow$$ Breadth of a cuboid $$(b)=y$$

$$\Rightarrow$$ Height of a cuboid $$(h)=z$$

$$\Rightarrow$$ Volume of cuboid $$=l\times b\times h$$

$$=x\times y\times z$$

$$=xyz$$
Question 7
1 / -0

The total surface area of a cube is ____ .

A
$$\displaystyle 3{ a }^{ 2 }$$

B
$$\displaystyle 6{ a }^{ 2 }$$

C
$$\displaystyle 4{ a }^{ 2 }$$

D
$$\displaystyle 5{ a }^{ 2 }$$

Solution

A cube has all edges of the same length. This means that each of the cube's six faces is a square. The total surface area is therefore six times the area of one face $$\displaystyle 6{ a }^{ 2 }$$ where $$a$$ is edge length of the cube.
Question 8
1 / -0

The area of a trapezium with height $$h$$ is:

A
$$\displaystyle\frac{h}{2}(\text{Sum of parallel sides})$$

B
$$\text{Sum of parallel sides}$$$$\times h$$

C
$$2h(\text{Sum of parallel sides})$$

D
$$\displaystyle\frac{1}{2}(\text{Sum of parallel sides}) +h$$

Solution

$$ABCD$$ is a trapezium.
Draw two perpendiculars from $$C$$ and $$D$$ on the side $$AB$$ intersecting $$AB$$ at points $$O$$ and $$N$$ respectively.
$$\therefore ONCD$$ is a rectangle and $$\triangle AOD$$ & $$\triangle BNC$$ are triangles.
Also, $$\triangle AOD \cong \triangle BNC$$

Area of rectangle $$ONCD = ON \times OD$$

Area of $$\triangle AOD$$ = $$\dfrac 12 \times AO \times OD$$

Area of $$ABCD$$ $$=ar(ONCD) + 2\ \times ar(\triangle AOD)$$

$$=(ON \times OD) + 2 \times \dfrac 12 \times AO \times OD$$

$$=\dfrac {OD}{2} \left[2 (ON) + 2(AO)\right]$$

$$=\dfrac h2 \left[(ON + 2(AO)) + ON \right]$$

$$=\dfrac h2 \left[AB + CD \right]$$

$$=\dfrac h2 \times \mbox{sum of parallel sides}$$
Question 9
1 / -0

Lateral surface area of a cylinder is

A
$$2\pi r^2$$

B
$$2\pi rh^2$$

C
$$2\pi rh$$

D
None

Solution

Area of lateral surface of cylinder $$=$$ Curved surface of cylinder
Curved surface of cylinder $$=$$ Circumference of circular base $$ \times $$ height
Therefore, lateral surface area of a cylinder $$=2 \pi r h$$
Question 10
1 / -0

A toy box can fit $$36$$ equal sized unit blocks in it. Then its volume is

A
$$36\,sq\,units$$

B
$$63\,sq\,units$$

C
$$36\,cu\,units$$

D
$$62\,cu\,units$$

Solution

$$\Rightarrow$$ Length of any edge of toy box $$(l)=1\,unit$$

$$\Rightarrow$$ Volume of $$1$$ toy box $$=(l)^3$$
$$=1\,cu\,units$$

$$\Rightarrow$$ Volume of $$36$$ equal sized toy box $$=36\times 1\,cu\,units$$
$$=36\,cu\,units$$.

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Mensuration Test - 14

Result

Mensuration Test - 14

Score

-

Rank

-

SHARING IS CARING

Question 1

Area of a cuboid

Area of a cube

Volume of a cuboid

None of these

Solution

Question 2

$$1$$

$$2$$

$$3$$

$$4$$

Solution

Question 3

20 cu cm

22 cu cm

28 cu cm

24 cu cm

Solution

Question 4

Formula of area of trapezium

Formula of perimeter of rectangle

Formula of the rhombus

Formula of area of square

Solution

Question 5

more than

less than

equal to

none of these

Solution

Question 6

$$\displaystyle \frac{xy}{z}$$

$$xyz$$

$$x + y + z$$

$$x - (y + z)$$

Solution

Question 7

$$\displaystyle 3{ a }^{ 2 }$$

$$\displaystyle 6{ a }^{ 2 }$$

$$\displaystyle 4{ a }^{ 2 }$$

$$\displaystyle 5{ a }^{ 2 }$$

Solution

Question 8

$$\displaystyle\frac{h}{2}(\text{Sum of parallel sides})$$

$$\text{Sum of parallel sides}$$$$\times h$$

$$2h(\text{Sum of parallel sides})$$

$$\displaystyle\frac{1}{2}(\text{Sum of parallel sides}) +h$$

Solution

Question 9

$$2\pi r^2$$

$$2\pi rh^2$$

$$2\pi rh$$

None

Solution

Question 10

$$36\,sq\,units$$

$$63\,sq\,units$$

$$36\,cu\,units$$

$$62\,cu\,units$$

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.