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Mensuration Test - 30

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Mensuration Test - 30
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Weekly Quiz Competition
  • Question 1
    1 / -0
    The addition of curved surface and circular surfaces are called

    Solution
    The total surface area includes curved surface area and two circular surfaces.
  • Question 2
    1 / -0
    Find the area of the trapezoid.

    Solution
    Area of trapezoid $$=$$ $$\dfrac{h(a+b)}{2}$$
    $$=$$ $$\dfrac{12(20+30)}{2}$$
    $$= 300$$ $$unit^2$$
  • Question 3
    1 / -0
    The area of the given diagram is

    Solution
    Given, $$UT=6$$ yd, $$RS=8$$ yd, height $$=7$$ yards
    Area of trapezoid $$=$$ $$\dfrac{1}{2}\times (l_{1}+l_{2})\times \text{height}$$
    $$=$$ $$\dfrac{1}{2}\times (6+8)\times 7$$
    $$=$$ $$\dfrac{1}{2}\times 14\times 7$$
    $$= 49$$ sq. yards
  • Question 4
    1 / -0
    Find the surface area of a cube in square inches, whose each edge measures $$3$$ inches.
    Solution
    Surface area of cube$$=6a^2$$
    Where '$$a$$' is the edge of the cube
    Surface area $$=$$ $$6\times (3)^2$$
    $$\Rightarrow 6\times 9=54$$ square inches
  • Question 5
    1 / -0
    What is the surface area of a cylinder that has a top and bottom if the height is $$8.5$$ units and the diameter is $$3$$ units?
    Solution
    Given: height $$= 8.5$$, diameter $$= 3$$
    $$\therefore$$ radius $$=$$ $$\dfrac{D}{2}=\dfrac{3}{2}=1.5$$
    Surface area $$=$$ $$2\pi rh +2\pi r^2$$
    $$=2\pi\times1.5\times 8.5+2\pi\times 1.5^2$$
    $$=2\pi(12.75+2.25)$$
    $$=2\pi(15)$$
    $$=30\pi$$ sq.units
  • Question 6
    1 / -0
    Figure $$ABCD$$ is a trapezoid with area $$50$$ square units. If the length of $$\overline{AB}$$ is $$6$$ units and the length of $$\overline {BC}$$ is $$5$$ units, what is the length of $$\overline {CD}$$?

    Solution
    Area of trapezoid $$=\dfrac { 1 }{ 2 } \left( AB+CD \right) \times BC=50$$ sq.units
    $$\Rightarrow \quad \dfrac { 1 }{ 2 } \left( 6+CD \right) \times 5=50\Rightarrow 6+CD=\dfrac { 50\times 2 }{ 5 } \Rightarrow CD=20-6=14$$ units.
  • Question 7
    1 / -0
    A closed metallic cylindrical box is 1.25 m high and its base radius is 35 cm. If the sheet metal costs Rs. 80 per m$$^2$$, the cost of the material used in the box is
    Solution
    T.S.A. of cyl $$ = 2\pi rh+2\pi r^{2} = 2\pi \times \left ( \dfrac{35}{100} \right )\times 1.25+2\pi \left ( \dfrac{35}{100} \right )^{2} $$
    $$ \Rightarrow TSA = 3.52\,m^{2} $$ & as cost of $$ 1\,m^{2} $$ is Rs 80 
    $$ \Rightarrow $$ Total cost $$ = 3.52\times 80 = Rs\,281.6 $$ 
  • Question 8
    1 / -0
    A room measures 11 ft x 12 ft x 9 ft. What is the volume?
    Solution

  • Question 9
    1 / -0
    The curved surface area of a right circular cone of radius $$11.3$$ cm is $$355$$ cm$$^2$$. What is its slant height?
    Solution
    Given, radius $$r=11.3 \text{ cm}$$

    and curved surface area $$=355 \text{ cm}^2$$.

    We know, curved surface area of a cone $$ =\pi rl $$

    $$11.3 \pi  l= 355$$

    $$l = \dfrac{355}{\pi \times 11.3}$$

    $$ {l = 10\text{ cm}} $$ 

    Therefore, option $$C$$ is correct.
  • Question 10
    1 / -0
    Each edge in a cube is $$5\ cm$$. What is the surface area in square cm?
    Solution
    Surface area of a cube is $$6a^2$$ where $$a$$ is an edge of the cube.

    The surface area of the cube with edge $$5$$cm is given by:

    $$A=6a^{ 2 }=6\times (5)^{ 2 }=6\times 25=150cm^{ 2 }$$
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