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Exponents and Powers Test - 11

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Exponents and Powers Test - 11
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Weekly Quiz Competition
  • Question 1
    1 / -0

    If (x + y)3 = 1331 and(x − y)5 = 243, then find x2 − y2.

    Solution

    (x+y)3 = 1331 ⇒ x + y = (1331)1/3 = 11 (x−y)5 = 243 ⇒x − y = (243)1/5 = 3 ⇒ (x + y) (x − y) = 11 × 3 = 33.

  • Question 2
    1 / -0

     If xyz = 0, then find the value of (ax)zy + (ay)zx + (az)xy

    Solution

    (ax)zy + (ay)zx + (az)xy = axyz + axyz + axyz  = 3 × axyz xyz = 0 ⇒ 3 × axyz = 3 × a = 3

  • Question 3
    1 / -0

     If 22n−3 = 2048, then (4n + 3n2) = ________

    Solution

    (a) 22n−3 = 2048 ⇒ 22n−3 = 211 ⇒ n = 7 ⇒ 4n + 3n2 = 4 × 7 + 3 × 72  = 28 + 147 = 175.

  • Question 4
    1 / -0

    If 22x−y = 32 and 2x + y = 16 then find x2 + y2 is equal to

    Solution

    22x−y = 32 ⇒ 2x − y = 5     ??..(1) ⇒ 2x + y = 16⇒ x + y = 4    ??(2) Adding (1) & (2)  ⇒ 3x = 9 ⇒ x = 3  

    ⇒ y = 4 − 3 = 1 ∴ x2 + y2 = 32 + 12 = 10

  • Question 5
    1 / -0

    (−9)3 ÷ (−9)8 is equal to

    Solution

    (−9)3 ÷ (−9)+ = (−9)3−8 = (−9)5.

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