Factorisation Test

Result

Factorisation Test - 4

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Weekly Quiz Competition

Question 1
1 / -0

Factorisation of xy − pq + qy − px is ______.

A
(y−p)(x+q)

B
(y−p)(x−q)

C
(y+p)(x+q)

D
(y+p)(x−q)

Solution

We have. xy − pq + qy − px = xy − px + qy − pq = x(y − p) + q(y − p) = (y − p)(x + q)
Question 2
1 / -0

The factors of 15x² − 26x + 8 are __.

A
(3x − 4)(5x + 2)

B
(3x − 4)(5x − 2)

C
(3x+4)(5x−2)

D
(3x+4)(5x+2)

Solution

15x² − 26x + 8 =15x² − 20x − 6x + 8 = 5x(3x − 4)−2(3x − 4) =(3x − 4)(5x − 2)
Question 3
1 / -0

he factors of x²−16 are __.

A
(x²+2)(x²−2)

B
(x+4)(x−4)

C
(x+2)(x−2)

D
Does not exist
Question 4
1 / -0

For x² + 2x + 5 to be a factor ofx⁴ + px² + q , the values of p and q must be _____.

A
-2, 5

B
5, 25

C
10, 20

D
6, 25

Solution

x² + 2x + 5 be a factor of x⁴ + px² + q So, other be x² − 2x + 5 So (x² − 2x + 5)(x² + 2x + 5)

=(x²+ 5)² − 4x² = x⁴ + 10x² + 25 − 4x²=x⁴ + 6x² + 25 So, p=6, q=25