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Playing with Numbers Test - 7

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Playing with Numbers Test - 7
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  • Question 1
    1 / -0
    Expanded form of $$920,831$$
    Solution
    The general form of six digits number will be, $$abcdef = a \times 100000 + b \times 10000 + c \times 1000 + d \times 100 +e \times 10+f$$
    Therefore, $$920831 = 900000+20000+800+30+1$$
  • Question 2
    1 / -0

       2   6
    $$\underline {\times M N}$$
    3    1   2
    'MN' is the representation for?
    Solution
    Since, in this question we are tested on the multiplication operation, we can multiply 26 with each of the given options to get the final answer.
    Shortcut: 
    Since, $$26\times MN=312$$, i.e., the product of 6 and N gives the last digit 2, thus N has to be either 2 or 7 because $$6 \times 2 = 12$$ and $$6 \times 7 = 42$$, where in both the cases unit's digit is 2.
    Thus options (1) and (4) are ruled out.
    Now, we can multiply 26 by 12 and 17 to get the answer.
    Hence, the answer is $$12$$.
  • Question 3
    1 / -0
    The expanded form of $$99$$ is
    Solution
    The general form of two digits number will be, $$ab= a \times 10 + b $$
    Therefore, $$99 = 10 \times 9 + 9$$
  • Question 4
    1 / -0
    Numbers ending with $$0$$ or $$5$$ are divisible by ___________.
    Solution
    Divisibility of 5 : Numbers ending with 0 and 5 are always divisible by 5
  • Question 5
    1 / -0
    Which of the following numbers are not divisible by $$9$$?
    $$36,90,157,243,514$$
    Solution
    If the sum of all the digits of a number is divisible by $$9$$ then the number is divisible by $$9$$.

    $$36$$
    $$3+6 = 9 = 9\times 1 ,$$ which is multiple of $$9$$

    $$90$$
    $$9+0 = 9 = 9\times 1 ,$$ which is multiple of $$9$$

    $$157$$
    $$1+5+7 = 13 , $$ which is not a multiple of $$9$$.

    $$243$$
    $$2+4+3 = 9 = 9\times 1 , $$which is multiple of $$9$$


    Hence, the correct answer is $$Option-(C)$$
  • Question 6
    1 / -0
    Which of the following number/s is/are not divisible by $$10$$?
    $$75,80,140,400,670$$
    Solution
    Numbers ending in $$0$$ are divisible by $$10$$.

    Hence, $$80,140,400,670$$ are divisible by $$10$$, while $$75$$ is not.
  • Question 7
    1 / -0
    Which of the following numbers are divisible by $$2$$ ?
    Solution
    Divisibility by 2:
    If the number contains an even number (0, 2, 4, 6, 8) in the units place, 
    then the number is completely divisible by $$2$$.

    All the options given here are even numbers i.e $$64$$ ends with $$4$$, 
    $$16$$ with $$6$$ and $$32$$ ends with $$2$$

    So, option D is correct.
  • Question 8
    1 / -0
    Which of the following numbers are divisible by $$2$$?
    Solution
    For a number to be divisible by $$2$$, it must contain an even digit in its unit place.
    Since, $$62$$ ends with $$2$$.
    Therefore, it is divisible by $$2$$.
    So, option B is correct.
  • Question 9
    1 / -0
    The general form of $$11$$ is
    Solution
    $$11 = 10 \times 1 + 1$$
    So, option C is correct
  • Question 10
    1 / -0
    Multiply the reverse of $$100$$ and $$2$$. The resulting number is
    Solution
    The reverse of $$100$$ is $$1$$.
    $$\therefore 1 \times 2 = 2$$
    So, option D is correct.
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