Linear Equations in One Variable Test - 1

Explanation:

5x+7/2=3/2x–14

By transposing the number and variable both

i.e. taking variables(x) on left hand side and numbers(7/2 and 14) on right hand side and changing the signs of transposing values

5x-3x/2= -14 - 7/2

L.c.m of both sides

(10x-3x)/2  = (-28-7)/2

7x/2  = -35/2

By cancelling  2 both sides

7x = -35        ( transpose 7 to other side in next step)

x = -35/7       (divide by 7)

x = -5.

Explanation:

 By transposing 3 to other side, it will be in denominator      

3x = 12

x=12/3 ( Now divide 12 by 3 )

x=4

Explanation:

By transposing numbers and variable both, their sign will change

2x− 3 =x+ 2

2x - x = 2 + 3

x = 5

Explanation:

by transposing,the signs will be change

2x-3=7

2x=7+3

2x=10

x=10/2

x=5.

The correct option is 5

Explanation:

For an equation to be valid it is necessary that  both values of R.H.S .and L.H.S MUST be equal. Hence an equation is an equality.

L.H.S. = R.H.S.

Explanation:

Since ratio = 2:5 is given

So let the numbers be 2x and 5x.    (Point to remember: if ratio is given let the numbers to be the same numeral value with the variable x)

5x−2x=66  ( difference between numbers is 66)

 or, 3x=66

by transposing  to other side

or, x=66/3

or,x=22

Numbers are 2x=44

                    5x=110

Two numbers are ​​​​44 and 110.

Explanation:

Let us suppose, unit digit's number is x

Tens digit's number is x+3

Then number is 10(x+3)+xIf the digits are interchanged then the number became10x+(x+3)

By condition,

10(x+3)+x+10x+(x+3)=143

or, 10x+30+x+10x+x+3=143

or, 22x+33=143

or,22x=143−33

or,22x=110

or,x=110/22

or,x=5

Then the number be10(5+3)+5=85

Explanation:

2y + 9 = 4.

By transposing

2y = 4 - 9

2y = -5       (transposing 2 to other side)

y = -5 / 2