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Linear Equations in One Variable Test - 22

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Linear Equations in One Variable Test - 22
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  • Question 1
    1 / -0
    When a number is divided by $$25$$, the result is $$-25$$. The number is:
    Solution
    Let the required number be $$ x$$.

    According to the question,
    $$\displaystyle \dfrac { x }{ 25 } =-25$$           

    $$\displaystyle x=-25\times 25$$              .......Multiply both sides by $$25$$

    $$\displaystyle x=-625$$
  • Question 2
    1 / -0
    Find $$v$$, if $$\displaystyle v+11=77-9v$$.
    Solution
    Given, $$\displaystyle v+11=77-9v$$.

    Transposing $$v$$ terms to one side, we get,
    $$\Longrightarrow\displaystyle v+9v=77-11 $$

    $$\Longrightarrow 10v=66$$

    $$\Longrightarrow\displaystyle v=\dfrac{66}{10}$$

    $$\therefore v=\dfrac{33}{5}$$.

    Hence, option $$A$$ is correct.
  • Question 3
    1 / -0
    If $$\displaystyle 4(3-n)=3n$$, then find the value of $$n$$.

    Solution
    Given, $$\displaystyle 4(3-n)=3n$$
    $$\Longrightarrow\displaystyle 12-4n=3n$$ ...[By Distribution Law].

    Transposing $$n$$ terms to one side, we get,
    $$\Longrightarrow\displaystyle -4n-3n=-12$$
    $$\Longrightarrow\displaystyle -7n=-12$$
    $$\Longrightarrow\displaystyle n=\dfrac{12}{7}$$.

    Hence, option $$C$$ is correct.
  • Question 4
    1 / -0
    The sum of four consecutive even integers is $$92$$. Find the largest number.
    Solution
    Let four consecutive even numbers be:
    $$\displaystyle x,x+2,x+4,x+6$$

    According to the question, 
    $$\displaystyle x+x+2+x+4+x+6=92$$

    $$\Longrightarrow\displaystyle 4x+12=92$$

    $$\displaystyle x=\dfrac{80}{4}=20$$

    $$\therefore$$ the largest number among them is  $$x+6$$ = $$20+6$$ = $$26$$
  • Question 5
    1 / -0
    $$10$$ is subtracted from the product of $$x$$ and $$9$$, the result is $$80$$. The number is 
    Solution
    According to the question, 
    $$\displaystyle 9x-10=80$$
    $$\Longrightarrow\displaystyle 9x=80+10$$ (on transposing)
    $$\Longrightarrow\displaystyle 9x=90$$
    $$\Longrightarrow\displaystyle x=\frac { 90 }{ 9 } =10$$
  • Question 6
    1 / -0
    Calculate the value of $$x$$, when $$2x+3=3x-4$$.
    Solution
    Given, $$\ 2x+3=3x-4$$.

    Transposing $$x$$ terms to one side, we get,
    $$\Rightarrow 2x-3x=-4-3$$

    $$\Rightarrow -x=-7$$

    $$\Rightarrow x=7$$.

    Hence, option $$E$$ is correct.
  • Question 7
    1 / -0
    Solve the equation: $$\dfrac{x+2}{2x}=1$$
    Solution
    Given, $$\dfrac{x+2}{2x}=1$$
    Multiplying both sides by $$2x$$, we obtain
    $$x + 2 = 2x$$
    $$2x - x = 2$$
    $$x = 2$$
  • Question 8
    1 / -0
    If $$x + 1 = 23$$, calculate the value of $$3x + 3$$.
    Solution
    Given that, $$x+1=23$$
    To find out: The value of $$3x+3$$

    $$x+1=23$$
    $$\therefore \ x=23-1=22$$

    Hence, $$3x+3 =3\left( 22 \right) +3\quad \quad [\because \ x=22]$$
    $$\Rightarrow 66+3=69$$

    Hence, if $$x+1=23$$, then the value of $$3x+3$$ is $$69$$.
  • Question 9
    1 / -0
    Find the value of $$x$$ which satisfies $$\displaystyle 5x+3=10x-17$$.
    Solution
    Given, $$5x+3=10x-17$$.

    Transposing $$x$$ terms to one side, we get,
    $$\Rightarrow 5x-10x=-17-3$$

    $$\Rightarrow -5x=-20$$

    $$\Rightarrow x=\dfrac{-20}{-5}$$

    $$\Rightarrow x=4$$.

    Hence, option $$D$$ is correct.
  • Question 10
    1 / -0
    Solve for $$x$$:
    $$\dfrac {7}{3x + 4} = \dfrac {7}{6x - 2}$$
    Solution
    Given,
    $$\dfrac { 7 }{ 3x+4 } =\dfrac { 7 }{ 6x-2 } $$
    $$\Rightarrow 42x-14=21x+28$$
    $$\Rightarrow 42x-21x=28+14$$
    $$\Rightarrow 21x=42$$
    $$\Rightarrow x=2$$
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