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Data Handling Test - 24

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Data Handling Test - 24
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  • Question 1
    1 / -0

    Directions For Questions

    The following pie graph shows the information about the participation of $$60$$ students of a school in various games during the sports day. Answer the question based on that:

    ...view full instructions

    In which game, least number of students took part?

    Solution
     $$Sports$$$$Participated \,Students$$
    $$(in\,degree)$$ 
     $$Shot-put$$$$60^o$$ 
     $$Running$$$$108^o$$ 
     $$Long\,Jump$$$$72^o$$ 
     $$Lemon\,and\,spoon$$$$90^o$$ 
     $$High-Jump$$$$30^o$$ 
    $$\Rightarrow$$  From above table we can see, in $$High-Jump$$ least number of students took part.
  • Question 2
    1 / -0

    Directions For Questions

    Based on the pie graph showing $$50$$ runs scored in cricket match, answer the following question:

    ...view full instructions

    In which over, not a single run was scored?

    Solution
     $$Overs$$$$Runs\,scored$$ 
     $$First$$$$6$$ 
     $$Second$$$$0$$ 
     $$Third$$$$12$$ 
     $$Fourth$$$$14$$ 
     $$Fifth$$$$18$$ 
    $$\Rightarrow$$  From above table we can see in second over not a single run was scored. 
  • Question 3
    1 / -0

    Directions For Questions

    The following pie graph shows the information about the participation of $$60$$ students of a school in various games during the sports day. Answer the question based on that:

    ...view full instructions

    How many students took part in lemon and spoon race?

    Solution
    $$\Rightarrow$$  Total number of students participated in sports $$=60$$ 
    $$\Rightarrow$$  Students who took part in lemon and spoon race ( in degree) $$=90^o$$
    $$\Rightarrow$$  Number of students who took part in lemon and spoon race $$=\dfrac{90^o}{360^o}\times 60$$
                                                                                                                $$=15\,students$$
  • Question 4
    1 / -0
    The given bar graph shows the number of matches played by different teams. Read the bar graph and answer the questions:
    How many matches did both India and Bangladesh play?

    Solution
    From the bar graph,
    The number of matches played by India $$=26$$.
    The number of matches played by Bangladesh $$=8$$.

    Therefore, the total number of matches played by both India and Bangladesh $$=26 + 8 = 34$$.

    Thus, total number of matches played by both India and Bangladesh $$34$$.

    Hence, option $$A$$ is correct.
  • Question 5
    1 / -0
    What temperature does the given thermometer shows?

    Solution
    Thermometer shows $$35^o C$$ or $$95^o F$$
    Hence the correct answer is option A.
  • Question 6
    1 / -0

    Directions For Questions

    The following pie graph shows the information about the participation of $$60$$ students of a school in various games during the sports day. Answer the question based on that:

    ...view full instructions

    In which game, maximum number of students took part?

    Solution
    $$\Rightarrow$$  Total number of students participated in sports $$=60$$
    $$\Rightarrow$$  In running maximum number of students took part which is $$108^o$$.
    $$\Rightarrow$$  Total number of students took part in running $$=\dfrac{108^o}{360^o}\times 60=18\,students$$
                                                                           
  • Question 7
    1 / -0

    Directions For Questions

    Based on the pie graph showing $$50$$ runs scored in cricket match, answer the following question:

    ...view full instructions

    In which over, $$28$$ percentage of tuns were scored?

    Solution
     $$Overs$$$$Runs\,scored$$ 
     $$First$$$$6$$ 
     $$Second$$$$0$$ 
     $$Third$$$$12$$ 
     $$Fourth$$$$14$$ 
     $$Fifth$$$$18$$ 
     $$Total$$$$50$$ 
    $$\Rightarrow$$  Total runs scored in $$5$$ overs $$=50$$
    $$\Rightarrow$$   $$\%$$ of runs scored in first over $$=\dfrac{6}{50}\times 100=12\% $$
    $$\Rightarrow$$   $$\%$$ of runs scored in second over $$=\dfrac{0}{50}\times 100=0\% $$
    $$\Rightarrow$$  $$\%$$ of runs scored in third over $$=\dfrac{12}{50}\times 100=24\% $$
    $$\Rightarrow$$  $$\%$$ of runs scored in fourth over $$=\dfrac{14}{50}\times 100=28\% $$
    $$\therefore$$   $$28\%$$ of runs scored in $$Fourth$$ over.
  • Question 8
    1 / -0
    Choose the correct answer from the alternatives given.
    What is the budget estimated by the family on clothing and grocery together?

    Solution
    Budget estimated on clothing and grocery $$= (8 + 20)\% = 28\%$$
    i.e $$28\%$$ of $$32000$$ 
    $$= \, \dfrac{28}{100} \, \times \, 32000 \, = \, Rs. 8960$$
  • Question 9
    1 / -0
    Choose the correct answer from the alternatives given.
    What is the difference in the amount estimated by family on electricity bill and cell bill?

    Solution
    Difference between electricity bill and cell bill $$= (19 - 6)\% = 13\%$$
    So, required difference $$=13\%\ of\ 32,000 = Rs.\ 4,160$$
  • Question 10
    1 / -0
    If $$P(A) = 1$$, then the event $$A$$ is known as
    Solution
    The probability is the possibility of an event happening when the probability of an event is 1, it means the event will occur for sure.
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