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Squares and Square Roots Test - 14

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Squares and Square Roots Test - 14
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  • Question 1
    1 / -0
    By splitting into prime factors, find the square root of $$5184$$.
    Solution

    Prime factorisation of $$5184$$ can be obtained as,

    $$ 5184 =2\times2\times2\times2\times2\times2\times3\times3\times3\times3$$

              $$= {2} ^{6} \times { 3 } ^ {4}  $$
    $$\therefore \sqrt {5184} = \sqrt {{2} ^{6} \times { 3 } ^ {4}} = {2} ^{3} \times { 3 } ^ {2} = 8 \times 9 = 72 $$

  • Question 2
    1 / -0
    Find the smallest number by which 2592 be multiplied so that the product is a perfect square.
    Solution
    $$\textbf{Step-1: Find the prime factorization of given expression & ungrouped pair.}$$
                     $$\text{We have given 2592}$$
                     $$\therefore$$  $$\text{Prime factorization of}$$ $$2592 = 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 3$$
                     $$\text{Now,}$$
                     $$\text{On grouping the factors in pairs, we notice that one 2 is left out.}$$
                     $$\text{So, we should multiply 2592 with 2, so that prime factor 2 gets grouped in pairs.}$$
    $$\textbf{Hence, 2592 should be multiplied by 2 to make it a perfect square.}$$ $$\textbf{Option - A}$$
  • Question 3
    1 / -0
    By splitting into prime factors, find the square root of $$396900$$
    Solution
    Prime factorisation of $$ 396900 = {2} ^{2} \times { 3 } ^ {4} \times { 5 } ^ {2} \times {7} ^ {2} $$
    $$ \sqrt {396900} = \sqrt {{2} ^{2} \times { 3 } ^ {4} \times { 5 } ^ {2} \times {7} ^ {2} } = 2 \times {3}^{2} \times 5 \times 7= 630 $$.
  • Question 4
    1 / -0
    Find the square root of $$324$$.
    Solution
    The prime factorization of 324 is given as
    $$324 = 2 \times 2 \times 3 \times 3 \times 3 \times 3$$
    $$\sqrt{324} = \sqrt{\left(2\times2 \right) \times \left(3\times3 \right) \times \left(3\times 3\right)}= 2 \times 3 \times 3 = 18$$
    $$\therefore \sqrt{324} = 18$$.
  • Question 5
    1 / -0
    Find the square root of $$4761$$.
    Solution
    $$\therefore \sqrt{4761} = 69$$

    or,
    Since the sum of digits of the given number is 18, therefore it is divisible by 3.
    $$\Rightarrow 4761 = 3\times 1587 = 3\times 3\times 529 = 3\times 3\times 23\times 23 = $$ square of $$23$$

  • Question 6
    1 / -0
    The square root of $$15129$$ is
    Solution
    $$\therefore \sqrt{15129} = 123$$

  • Question 7
    1 / -0
    The square root of $$34969$$ is:
    Solution
    $$\therefore \sqrt{34969} = 187$$
    or 
    $$34969=11\times 11\times 17\times 17$$
    $$\sqrt{34969}=\sqrt{11\times 11\times 17\times 17}$$
                    $$=11\times 17=187$$

  • Question 8
    1 / -0
    Find the square root of $$1156$$.
    Solution
    So, the square root of $$1156$$ is $$34$$.

  • Question 9
    1 / -0
    The square root of $$69696$$ is
    Solution
    $$\therefore \sqrt {69696}=264$$

  • Question 10
    1 / -0
    The square root of $$7744$$ is
    Solution
    $$\therefore \sqrt{7714} = 88$$

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