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Algebraic Expressions and Identities Test - 3

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Algebraic Expressions and Identities Test - 3
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  • Question 1
    1 / -0

    Area of the rectangle whose length 4ab and breadth 6ab is

    Solution

    Area of rectangle = length × breadth

    = 4ab × 6ab

    = 24a2b2

    Hence, D is the correct answer.

     

  • Question 2
    1 / -0

    Find the product: 101 × 99

    Solution

    We know that, (a + b) (a – b) = a2 – b2

    101 × 99 = (100 + 1) (100 – 1)

    = (100)2 – (1)2

    = 10000 – 1

    = 9999

    Hence, B is the correct answer.

     

  • Question 3
    1 / -0

    The product (x – 2) (x + 2) (x2 + 4) (x4 + 16) is

    Solution

    Given: (x – 2) (x + 2) (x2 + 4) (x4 + 16)

    We know that, (a + b) (a – b) = a2 – b2

    So,

    (x – 2) (x + 2) (x2 + 4) (x4 + 16) = (x2 – 4) (x2 + 4) (x4 + 16)

    = (x4 – 16) (x4 + 16)

    = x8 – 256

    Hence, B is the correct answer.

     

  • Question 4
    1 / -0

    If (a - b) = 4 and ab = 2, then find the value of a2 + b2.

    Solution

    We know that, (a - b)2 = a2 + b2 - 2ab

    (4)2 = a2 + b2 – 2 × 2

    a2 + b2 = 16 + 4

    = 20

    Hence, D is the correct answer.

     

     

  • Question 5
    1 / -0

    Find the product (7x + y) × (x + 7y)

    Solution

    (7x + y) × (x + 7y) = 7x × (x + 7y) + y × (x + 7y)

    = 7x2 + 49xy + xy + 7y2

    = 7x2 + 7y2 + 50xy

    Hence, A is the correct answer.

     

     

  • Question 6
    1 / -0

    Simplify: (x – 5)(x + 5) + 25

    Solution

    (x – 5)(x + 5) + 25 = x × (x + 5) – 5 × (x + 5) + 25

    = x2 + 5x – 5x – 25 + 25

    = x2

    Hence, B is the correct answer.

     

  • Question 7
    1 / -0

    (a + b)(a – b) + (a2 + b2) equals

    Solution

    (a + b)(a – b) + (a2 + b2) = a × (a – b) + b × (a – b) + (a2 + b2)

    = a2 – ab + ab – b2 + (a2 + b2)

    = 2a2

    Hence, C is the correct answer.

     

  • Question 8
    1 / -0

    (a + b) (c – d) + (a – b) (c + d) + 2 (ac + bd) equals

    Solution

    (a + b)(c – d) = a × (c – d) + b × (c – d)

    = ac – ad + bc – bd

    (a – b)(c + d) = a × (c + d) – b × (c + d)

    = ac + ad – bc – bd

    (a + b) (c – d) + (a – b) (c + d) = ac – ad + bc – bd + ac + ad – bc – bd

    = 2ac – 2bd

    (a + b) (c – d) + (a – b) (c + d) + 2 (ac + bd) = 2ac – 2bd + 2ac + 2bd

    = 4ac

    Hence, C is the correct answer.

     

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