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Algebraic Expressions and Identities Test - 37

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Algebraic Expressions and Identities Test - 37
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  • Question 1
    1 / -0
    The product of $$4{ a }^{ 2 }$$, $$-6{ b }^{ 2 }$$ and $$3{ a }^{ 2 }{ b }^{ 2 }$$ is
    Solution
    $$4a^{2}\times (-6b^{2})\times 3a^{2}b^{2}$$
    $$=4\times a\times a\times -6\times b\times b\times 3\times a\times a\times b\times b$$
    $$=4\times -6\times 3\times a\times a\times a\times a\times b\times b\times b\times b$$
    $$=-72 a^{4}b^{4}$$
  • Question 2
    1 / -0
    The value of the product $$\left( 4{ a }^{ 2 }+3b \right) \left( 9{ b }^{ 2 }+4a \right) $$ at $$a=1$$, $$b=-2$$ is
    Solution
    $$(4a^{2}+3b)(9b^{2}+4a)$$
    $$=36a^{2}b^{2}+27b^{3}+16a^{3}+12ab$$

    Put the value of $$a=1$$ and $$b=-2$$, we get
    $$(4a^{2}+3b)(9b^{2}+4a)\\$$
    $$=36\times (1)^{2}\times (-2)^{2}+27\times (-2)^{3}+16\times (1)^{3}+12\times (1)\times (-2)\\$$
    $$=36\times 4-27\times 8+16\times 1-12\times 2\\$$
    $$=144-216+16-24=-80$$
  • Question 3
    1 / -0
    The expression $$\displaystyle -8{ x }^{ 3 }\left( 7{ x }^{ 6 }-3{ x }^{ 5 } \right) $$ equals:
    Solution
    The expression equals $$-8x^3(7x^6-3x^5)$$
    $$\Rightarrow -56x^{3+6}+24x^{3+5}$$
    $$\Rightarrow -56x^9+24x^8$$
  • Question 4
    1 / -0
    The product of the monomials $$\displaystyle \left( 2{ x }^{ 4 }y \right)$$  and $$\left( 3{ x }^{ 5 }{ y }^{ 8 } \right) $$ is :
    Solution
    The product of monomials $$2x^4y$$ and $$3x^5y^8$$ is
    $$ 2x^4y\times 3x^5y^8= 2(3).x^4(x^5).y^1(y^8)$$
    $$\Rightarrow 6x^{4+5}y^{1+8}$$
    $$\Rightarrow 6x^9y^9$$
  • Question 5
    1 / -0
    Number of terms in the expansion $$\left( a+b \right) \left( c+d \right) $$ is ________.
    Solution
    given, $$(a+b)(c+d)$$

    $$=ac+bc+ad+bd$$

    In above expression the number of terms are Four (4)
  • Question 6
    1 / -0
    Expand  the expression $$4(5x+3)(2x-1)$$.
    Solution
    On expanding, we get
    $$ 4(5x+3)(2x-1)$$
    $$\Rightarrow 4(10x^2+6x-5x-3)$$
    $$\Rightarrow 4(10x^2+x-3)$$
    $$\Rightarrow 40x^2+4x-12$$
  • Question 7
    1 / -0
    Multiply the binomials $$\displaystyle \left( 4z+3 \right) $$ and $$\left( z-2 \right) $$ :
    Solution
    On multiplying, $$(4z+3)(z-2)$$
    $$\Rightarrow 4z(z-2)+3(z-2)$$
    $$\Rightarrow 4z^2-8z+3z-6$$
    $$\Rightarrow 4z^2-5z-6$$
  • Question 8
    1 / -0
    Find the product of $$(15x-11)$$ and $$(6-5x)$$.

    Solution
    The product of $$(15x - 11) \times (6 - 5x)$$
    $$= 15x(6 - 5x) - 11(6 - 5x)$$
    $$= 90x - 75x^2 - 66 + 55x$$
    $$= -75x^2 + 145x - 66$$
  • Question 9
    1 / -0
    $$-4p\left( 3q-5p \right) =$$
    Solution
    Multiplying $$-4p$$ with $$(3q-5p)$$
    $$-4p(3q) = -12pq$$ $$-4p(-5p)$$
                    $$= -12pq+20p^2$$
  • Question 10
    1 / -0
    What is the product $$(x + 2)(x - 3)$$?
    Solution
    $$(x+a)(x+b)$$ $$=$$$$x^2+(a+b)x+ab$$
    In this formula, taking $$x=x$$ $$a= 2$$ $$b= (-3)$$
    $$(x+2)(x-3)$$ = $$x^2+[(2+ (-3)]x+2(-3)$$
    $$\Rightarrow$$ $$x^2-1x-6$$
    $$\Rightarrow$$ $$\boxed{x^2-x-6}$$
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