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Algebraic Expressions and Identities Test - 4

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Algebraic Expressions and Identities Test - 4
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  • Question 1
    1 / -0

    Evaluate: 4xy × 8x2y3z × 2z × ½xyz

    Solution

    Given: 4xy × 8x2y3z × 2z × ½xyz

    4xy × 8x2y3z × 2z × ½xyz = 4 × 8 × 2 × ½ × xy × x2y3z × z × xyz

    = 32 × x1+2+1 × y1+3+1 × z1+1+1

    = 32x4y5z3

    Hence, c is the correct answer.

     

  • Question 2
    1 / -0

    If the dimensions of a box are (x – 1), 2x and 3yz then find the volume of the box.

    Solution

    The volume of box = Length × Breadth × Height

    = (x – 1) × 2x × 3yz

    = (x – 1) × 6xyz

    = x × 6xyz – 1 × 6xyz

    = 6x2yz – 6xyz

    Hence, C is the correct answer

     

  • Question 3
    1 / -0

    Find the value of the expression: s(s – 1)(s + 1) + 2s + s2 (s + 1) at s = 3.

    Solution

    Given expression: s(s – 1)(s + 1) + 2s + s2 (s + 1)

    s(s – 1)(s + 1) + 2s + s2 (s + 1) = (s2 – s)(s + 1) + 2s + s3 + s2

    = s2(s + 1) – s(s + 1) + 2s + s3 + s2

    = s3 + s2 – s2 – s + 2s + s3 + s2

    = 2s3 + s2 + s

    At s = 3,

    = 2 × 27 + 9 + 3

    = 54 + 12

    = 66

    Hence, C is the correct answer.

     

     

  • Question 4
    1 / -0

    Which of the following is correct?

    Solution

    Expression that contains three terms is called trinomial.

    (xy + yz + zx) has three terms, xy, yz and zx.

    Hence, D is the correct answer.

     

  • Question 5
    1 / -0

    Which of the following is a binomial?

    Solution

    An expression that contains two terms is called binomial.

    2x + y has two terms as 2x and y.

    Hence, C is the correct answer.

     

  • Question 6
    1 / -0

    Write the coefficient of x2 in the following expression:

    x75 – x2 + 3x44 + x – 5x2 + 100

    Solution

    Given Expression: x75 – x2 + 3x44 + x – 5x2 + 100

    We can add the coefficients of x2, and we will have,

    x75 – 6x2 + 3x4 + x + 100

    So, the coefficient of x2 is -6.

    Hence, C is the correct answer.

     

  • Question 7
    1 / -0

    Add the following: ab – bc, bc – ca, ca – ab

    Solution

    To Find: ab – bc + bc – ca + ca – ab

    Therefore,

    ab – bc + bc – ca + ca – ab = ab – ab + bc – bc + ca – ca

    = 0 + 0 + 0

    = 0

    Hence, D is the correct answer.

     

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