Circles Test - ...

$$ABCD$$ is a cyclic quadrilateral such that $$AB$$ is a diameter of the circle circumscribing it and $$\displaystyle \angle ADC=140^{\circ}$$, then $$\displaystyle \angle BAC$$ is equal to:

Any cyclic parallelogram is a ______.

In the given figure, ABCD is a cyclic quadrilateral and PQ is tangent to the circle with centre 'O'. BD is diameter, $$\angle DCQ = 40^o , \angle ABD = 60^o$$. The $$\angle BCP=$$ _______. 

In the diagram, O is the centre of the circle. Find the value of $$x$$.

In the given figure, O is centre of the circle, then $$\angle XOZ $$ is ________.

In the give figure, ABCD is a cyclic quadrilateral, $$
\angle C B Q=48^{\circ}
 $$ and a=2b. Then, b is equal to

The circumcirlce of the quadrilateral formed by the lines $$x = a,x = 2a,y =  - a,y = a$$ is 

In the given figure, in $$  \square  $$ pors.if $$  \angle R S P=80^{\circ}  $$ then $$  \angle R Q T= $$____________

Distance between chords of contact of the tangents of the circle $$ x ^ { 2 } + y ^ { 2 } + 2 y x + 27 y + c = 0 $$ from the origin and the point ($$g, f$$) is

Two tangents $$PQ$$ and $$PR$$ drawn to the circle $$x^2+y^2-2x-4y-20=0$$ from the point $$P(16,7)$$. If is the centre of the circle, area of quadrilateral $$PQCR$$ is