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Surface Areas and Volumes Test - 36

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Surface Areas and Volumes Test - 36
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Calculate the total surface area of the cuboid:

    Solution
    Total surface area of the cuboid $$\displaystyle 2\times \left( lw+lh+hw \right) $$
    $$\displaystyle =2\times \left( 10\times 1+10\times 7+7\times 1 \right) $$
    $$\displaystyle =2\times \left( 10+70+7 \right) $$
    $$\displaystyle =2\times 87$$
    $$=\displaystyle 174{ cm }^{ 2 }$$

    So, option D is correct.
  • Question 2
    1 / -0
    The side of the base of a dice is $$5.5$$ mm. Find the surface area of a dice whose edges are squares.
  • Question 3
    1 / -0
    Find the surface area of a cube with side $$\displaystyle 12$$ m
    Solution
    Total surface area of a cube $$=$$ $$\displaystyle 6\times $$ side$$^{ 2 }$$
    $$\displaystyle =6\times 12\times 12$$
    $$\displaystyle =864{ m }^{ 2 }$$
  • Question 4
    1 / -0
    A cubical water tank measures $$3$$ feet sides. Find its surface area.
    Solution
    $$Surface\ area\ of\ a\ cube=6\times Side^2$$
    $$side=3ft$$
    $$Surface\ Area=6\times 3^2$$
    $$Surface\ Area=6\times 9$$
    $$Surface\ Area=54ft^2$$
  • Question 5
    1 / -0
    The length of the side is $$3.9$$ ft. Find the surface area of a cube .
  • Question 6
    1 / -0
    The curved surface of a cylinder is $$\displaystyle 1000{ \ mm }^{ 2 }$$ and the radius is $$20$$ mm. Find height of the cylinder. (Round off the answer to nearest whole number).
    Solution
    Curved surface area of cylinder is $$A=2πrh$$

    Here, the curved surface area is $$A=1000$$ mm$$^2$$ the radius is $$r=20$$ mm.

    Thus,

    $$A=2πrh\\ \Rightarrow 1000=2\times \frac { 22 }{ 7 } \times 20\times h\\ \Rightarrow 1000\times 7=2\times 22\times 20\times h\\ \Rightarrow 7000=880\times h\\ \Rightarrow h=\frac { 7000 }{ 880 } =7.96$$

    Hence, height of the cylinder is $$7.96$$ mm.

  • Question 7
    1 / -0
    The diameter of a cylinder is $$12$$ m and its height is $$10$$ m. Find the curved surface area of a cylinder.
    Solution
    Curved surface area of cylinder is $$A=2πrh$$

    Here, the diameter is $$12$$ m and therefore, the radius is half of diameter that is $$r=6$$ m and height is $$10$$ m.

    Thus,

    $$A=2πrh=2\times π\times 6\times 10=120π$$ m$$^2$$

    Hence, the curved surface area of the cylinder is $$120π$$ m$$^2$$.

  • Question 8
    1 / -0
    Choose the correct formula for surface area of a cylinder.
    Solution
    A cylinder comprises two circles and one rectangle as given in the figure
    The surface area of a circle is $$\pi r^2$$ where $$r$$ is the radius and the surface area of a rectangle is $$2\pi rh$$.
    $$\implies$$ Surface area of cylinder $$=2\times$$ area of the circular base $$+$$ area of the rectangle
    $$\Rightarrow $$ Surface area of cylinder $$=2\pi r^2+2\pi rh$$

  • Question 9
    1 / -0
    Find the area of the curved surface of a cylindrical box with radius 12 inches and height 20 inches.
    Solution
    Curved surface area of cylinder is $$A=2πrh$$

    Here, the radius is $$12$$ in and height is $$20$$ in.

    Thus,

    $$A=2πrh=2\times 3.14\times 12\times 20=1507.2$$ in$$^2$$

    Hence, the curved surface area of the cylinder is $$1507.2$$ in$$^2$$.

  • Question 10
    1 / -0
    Find the surface area of the cylinder shown above:

    Solution
    Given: Radius of cylinder $$r=0.1m$$ and Height $$h=2.2m$$.
    Surface area of a cylinder = $$\displaystyle 2\pi r\left( r+h \right) $$
    $$\displaystyle =2\times \pi \times 0.1\left( 0.1+2.2 \right) $$
    $$\displaystyle =2\times \pi \times 0.1\left( 2.3 \right) $$
    $$\displaystyle =0.46\pi { m }^{ 2 }$$

    So, option C is correct.
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