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Statistics Test - 5

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Statistics Test - 5
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  • Question 1
    1 / -0

    Class size of a distribution having 28, 34, 40, 46 and 52 as its class marks is

    Solution

    class size is the difference between two consecutive values of the class mark.

    Here, the difference between two consecutive class mark is 6

    i.e 34 − 28 = 6

  • Question 2
    1 / -0

    Given the class intervals 0-10, 10-20, 20-30,…, then 10 is considered in class

    Solution

    As the classes are continuous, the upper limits does not include in that particular class.

  • Question 3
    1 / -0

    Given the class intervals 1-10, 11-20, 21-30, …, then 20 is considered in class

    Solution

    In a discontinuous class both lower and upper limits belong to that particular class.

  • Question 4
    1 / -0

    The class marks of a frequency distribution are as given below: 38, 43, 48, 53, 58. The class corresponding to the class mark 43 is

    Solution

    As the class size = 5, Class interval is got by subtracting and adding 2.5 to 43

  • Question 5
    1 / -0

    The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is

    Solution

    The classes are 10-15,15-20,20-25,25-30,30-35 so that upper limit of the highest class is 35

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