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Polynomials Test - 10

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Polynomials Test - 10
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  • Question 1
    1 / -0

    If x-1 if the factor of p(x)= x− 23x+ kx−120, then the value of ‘k’ is

    Solution

    If x - 1is a factor of p(x), then

    p(1) = 0

    (1)3 - 23 (1)2 + k (1) - 120 = 0

    1 - 23 + k - 120 = 0

    1 - 143 + k = 0

    -142 + k = 0

    k = 142

     

  • Question 2
    1 / -0

    If f(x) = x2−5x + 1, then the value of f(2) + f(-1) is

    Solution

    f(x) = x− 5x+1

    f(2) + f(−1)

    = (2)2−5×2+1+(−1)2−5×(−1)+1

    = 4−10+1+1+5+1

    = 12−10

    = 2

     

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