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Polynomials Test - 26

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Polynomials Test - 26
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  • Question 1
    1 / -0
    Zero's of the polynomial p(x) =$$x^{2}$$-2x is / are :
    Solution
    Zeros of the polynomial $$x^2-2x=p(x)$$

    $$x^2-2x=0$$

    $$\Rightarrow x(x-2)=0$$

    $$\Rightarrow x=0$$ or $$x=2$$

    $$\therefore$$ Zeros of polynomial $$p(x)$$ are $$0$$ and $$2$$
  • Question 2
    1 / -0
    The degree of the polynomial $$x^2-5x^4+\dfrac{3}{4}x^7-73x+5$$ is 
    Solution
    The degree of a polynomial is the highest degree of its monomials.
    Degree of $${x}^{2}$$ is  $$2$$
    Degree of $$-5{x}^{4}$$ is $$4$$
    Degree of $$\dfrac{3}{4}{x}^{7}$$ is $$7$$
    Degree of $$-73x$$ is $$1$$
    Degree of $$5$$ is $$0$$
    The highest degree of the polynomial is $$7$$.
  • Question 3
    1 / -0
    Sum of zeros of the polynomial $$x^2-6$$ is _______ 
    Solution
    For $$ax^2+bx+c=0$$ where $$a\neq0$$, the sum of roots is given by: $$\dfrac{-b}{a}$$.

    Here, $$b=0$$, therefore, sum of roots $$=0$$
  • Question 4
    1 / -0
    What is the degree of the polynomials $$\sqrt 7 $$?
    Solution

  • Question 5
    1 / -0
    The expression with only constant is
    Solution

  • Question 6
    1 / -0
    The zero of polynomial $$9x+2$$ is
    Solution
    The polynomial given is $$9x+2$$
    to find the zero of polynomial we need to equate the polynomial to zero 

    $$\Rightarrow 9x+2=0$$

    $$\Rightarrow 9x=-2$$

    $$\Rightarrow x=\dfrac {-2}9$$

    the zero of the polynomial is $$\dfrac{-2}{9}$$
  • Question 7
    1 / -0
    The degree of the polynomial $$3x^3y-5xy^4-2x+1$$ is
    Solution
    The degree of the polynomial
    $$3x^3y-5xy^4-2x+1$$ is of $$-5xy^4\implies1+4=5$$  [as it is the highest]
  • Question 8
    1 / -0
    A cubic polynomial has at most
    Solution
    The third degree polynomial function has maximum of $$3$$ zeros
    Example: $$x^3-9x=0$$
    $$x(x^2-9)=0$$
    $$x=0, x=±3$$
    Therefore, there are $$3$$ zeroes in cubic polynomial.
  • Question 9
    1 / -0
    Zero of the polynomial $$p( x) = 3x +5$$ is :
    Solution
    Zero of the polynomial $$p(x)$$ is the value of variable $$x$$ at which $$p(x)=0$$.
    $$\Rightarrow 3x+5=0$$
    $$\Rightarrow 3x=-5$$
    $$\Rightarrow x=\dfrac{-5}{3}$$.

    Therefore, option $$D$$ is correct.
  • Question 10
    1 / -0

    If $$p(x) = x^2 -2 \sqrt {2}x + 1$$, then $$p(2\sqrt 2)$$ is equal to

    Solution
    $$p(x)=x^{ 2 }-2\sqrt { 2 } x+1$$
    $$p(2\sqrt { 2 } )=+2\sqrt { 2 } ^{ 2 }-2\sqrt { 2 }\times2\sqrt { 2 } +1$$
    $$p(2\sqrt { 2 } )=8-8+1$$
    $$p(2\sqrt { 2 } )=1$$
    Hence, option B.
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