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Triangles Test - 13

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Triangles Test - 13
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  • Question 1
    1 / -0

    If a,b,c are the lengths of the sides of a triangle, then

    Solution

    Put the sidesof triangle a,b,c

    for a possible triangle the following are possible.

    a+b> = c

    b+c> = a 

    a+c> = b

     

  • Question 2
    1 / -0

    It is not possible to construct a triangle when the lengths of its sides are

    Solution

    Put the sidesof triangle a,b,c

    for a possible triangle the following are should possible.

    a+b>=c

    b+c>=a

    a+c>=b

    here 2.2+3.1=5.3

    so a+b=c

    so the triangle becomes a streight line.

    so we cannot draw a triangle with sides 5.3cm, 2.2cm, 3.1cm

     

  • Question 3
    1 / -0

    If triangle PQR is right angled at Q, then

    Solution

    then the hypotnuse should be always greater than the remaining two sides.

     

  • Question 4
    1 / -0

    If triangle ABC is obtuse angled and ∠C is obtuse, then

    Solution

    Side opposite to the largest angle is always greatest and a traingle can have only 1 angle as obtuse

     

  • Question 5
    1 / -0

    In △ABC, if ∠B = 30º and ∠C = 70º , then which of the following is the longest side?

    Solution

    Since the sum of all sides of a triangle is 180°.

    So,  angle C=70° ,angle B=30°,angle A=80°.

    We have a theorem which states that the side opposite to the greatest angle is the longest.

    So, the side opposite to angle A is the longest.

     

  • Question 6
    1 / -0

    In △ABC, if ∠A = 45 and ∠B = 70 , then the shortest and the longest sides of the triangle are respectively,

    Solution

    Smallest angle is A and greatest angle is B and hence sides opposite to these angles are BC and AC and they are shortest and longest respectively

     

  • Question 7
    1 / -0

    ∠x and ∠y are exterior angles of a triangle ABC at the points B and C res. Also, ∠B > ∠C, then relation between ∠x and ∠y is:

    Solution

    Since interior angle B >interior angle C hence X<y

     

  • Question 8
    1 / -0

    If the bisector of the angle A of a △ABC is perpendicular to the base BC of the triangle then the triangle ABC is :

    Solution

    Angle bisector is perpendicular to the  opposite side only in equilateral triangle

     

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