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Triangles Test - 17

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Triangles Test - 17
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  • Question 1
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    Use the following information to answer the next question.

    In the given figure, BE||FC and DE||AF.

    If BC = 2 cm and AD = 8 cm, then what is the perimeter of hexagon AFCDEBA?

    Solution

    In ΔDBE and ΔACF:

    ∠DBE = ∠ACF (Alternate interior angles)

    ∠EDB = ∠FAC (Alternate interior angles)

    BE = CF = 9 cm

    ∴ ΔDBE ≅ ΔACF (ASA Congruence rule)

    ⇒ ED = FA and DB = AC (CPCT)

    ∴ ED = 7 cm

    Now, DB = AC

    ∴ DC + CB = AB + BC

    ⇒ DC = AB … (1)

    It is given that AD = 8 cm.

    ∴ AB + BC + CD = 8 cm

    ⇒ DC + 2 cm + CD = 8 cm

    ⇒ 2CD = 6 cm

    ⇒ CD = 3 cm

    ∴ AB = 3 cm

    Perimeter of hexagon AFCDEBA = AF + FC + CD + DE + EB + BA

    = (7 + 9 + 3 + 7 + 9 + 3) cm

    = 38 cm

    Thus, the perimeter of hexagon AFCDEBA is 38 cm.

    The correct answer is A.

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