Motion Test

Result

Motion Test - 18

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Weekly Quiz Competition

Question 1
1 / -0

A particle is moving in a circular path of radius r. The displacement after half a circle would be:

A
Zero

B
π r

C
2 r

D
2π r

Solution

After half a circle, the particle will be diametrically opposite to its origin. Hence, displacement is equal to diameter.
Question 2
1 / -0

A body is thrown vertically upward with velocity u, the greatest height h to which it will rise is,

A
\( u\over\ g\)

B
\(u^2\over\ 2g\)

C
\(u^2\over\ g\)

D
\(u\over\ 2g\)

Solution

At highest point, v = 0

Using \(v^2– u^2\) = 2as, we get

0- \(u^2\)=2(-g)h( here a = -g and s=h)

or \(h = {u^2\over\ 2g}\)
Question 3
1 / -0

The numerical ratio of displacement to distance for a moving object is

A
Always less than 1

B
Always equal to 1

C
Always more than 1

D
Equal or less than 1

Solution

Displacement can be equal or less than distance but it will never be more than distance.
Question 4
1 / -0

If the displacement of an object is proportional to square of time, then the object moves with

A
Uniform velocity

B
Uniform acceleration

C
Increasing acceleration

D
Decreasing acceleration

Solution

Velocity is measured in terms of distance per second, while acceleration is measured in terms of distance per square second.

Hence, uniform acceleration is the correct answer.
Question 5
1 / -0

Suppose a boy is enjoying a ride on a merry-go-round which is moving with a constant speed of \(10 \,m s^{–1}\). It implies that the boy is

A
At rest

B
Moving with no acceleration

C
In accelerated motion

D
Moving with uniform velocity

Solution

The merry-go-round moves in a circular path with constant speed, but its velocity changes due to the change in the direction of motion at every point. It implies that the boy on merry-go-round is in accelerated motion.
Question 6
1 / -0

Area under a v – t graph represents a physical quantity which has the unit

A
\(m^2\)

B
m

C
\(m^3\)

D
\(m\, s^{–1}\)

Solution

Area under v-t graph represents distance and unit of distance is metre (m).
Question 7
1 / -0

Slope of a velocity – time graph gives

A
The distance

B
The displacement

C
The acceleration

D
The speed

Solution

Slope of a velocity-time graph gives the rate of change of velocity or the acceleration.
Question 8
1 / -0

In which of the following cases of motions, the distance moved and the magnitude of displacement are equal?

A
If the car is moving on straight road

B
If the car is moving in circular path

C
The pendulum is moving to and fro

D
The earth is revolving around the Sun

Solution

If the car is moving on straight road, the distance moved and the magnitude of displacement are equal.
Question 9
1 / -0

Rate of change of displacement is called

A
Speed

B
Deceleration

C
Acceleration

D
Velocity

Solution

Rate of change of displacement is called Velocity.
Question 10
1 / -0

SI Unit of measurement of acceleration is

A
\(m\over\ s\)

B
\(m\over\ s^2\)

C
\(m\over\ hr\)

D
M

Solution

SI Unit of measurement of acceleration is \(m\over\ s^2\)
Question 11
1 / -0

The average velocity of a body is given by the expression :

A
V= u + at

B
\(2as= {v^2 \over u^2}\)

C
\(V_{av} = {(u + v)\over\ 2}\)

D
\(S= ut + ½ \,a t^2\)

Solution

The average velocity of a body is given by the expression \(V_{av} = {(u + v)\over\ 2}\)
Question 12
1 / -0

A scalar quantity has ______________

A
Magnitude only

B
Direction only

C
Both direction and magnitude

D
None of these

Solution

A scalar quantity has Magnitude only.

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Re-Attempt Weekly Quiz Competition

Motion Test - 18

Result

Motion Test - 18

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Question 1

Zero

π r

2 r

2π r

Solution

Question 2

\( u\over\ g\)

\(u^2\over\ 2g\)

\(u^2\over\ g\)

\(u\over\ 2g\)

Solution

Question 3

Always less than 1

Always equal to 1

Always more than 1

Equal or less than 1

Solution

Question 4

Uniform velocity

Uniform acceleration

Increasing acceleration

Decreasing acceleration

Solution

Question 5

At rest

Moving with no acceleration

In accelerated motion

Moving with uniform velocity

Solution

Question 6

\(m^2\)

m

\(m^3\)

\(m\, s^{–1}\)

Solution

Question 7

The distance

The displacement

The acceleration

The speed

Solution

Question 8

If the car is moving on straight road

If the car is moving in circular path

The pendulum is moving to and fro

The earth is revolving around the Sun

Solution

Question 9

Speed

Deceleration

Acceleration

Velocity

Solution

Question 10

\(m\over\ s\)

\(m\over\ s^2\)

\(m\over\ hr\)

M

Solution

Question 11

V= u + at

\(2as= {v^2 \over u^2}\)

\(V_{av} = {(u + v)\over\ 2}\)

\(S= ut + ½ \,a t^2\)

Solution

Question 12

Magnitude only

Direction only

Both direction and magnitude

None of these

Solution