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Motion Test - 4

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Motion Test - 4
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  • Question 1
    1 / -0

    What do you infer, if s-t graphs of two cyclists meet at a point?

    Solution

    If S-t graphs of two cyclists meet at a point, then it implies that they pass each other.­

     

  • Question 2
    1 / -0

    What is the direction of velocity in a circular motion at any point?

    Solution

    The direction of velocity in a circular motion at any point is along the tangent drawn at that point.

     

  • Question 3
    1 / -0

    If a person walked at a speed of 2 m/s for 12 s. What distance that person must have travelled?

    Solution

    Distance =  speed × time

    = 2 m/s × 12 s

    = 24 m

     

  • Question 4
    1 / -0

    Rate of change of displacement with time is called

    Solution

    Rate of change of displacement with time is called velocity.

     

  • Question 5
    1 / -0

    Alex walks along a curved path and takes several turns while walking from home to school. How can you best describe his displacement?

    Solution

    To define displacement we need both: the distance travelled and the direction.

     

  • Question 6
    1 / -0

    A boy throws a ball up and catches it when the ball falls back. In which part of the motion the ball is accelerating?

    Solution

    As the ball goes up, its speed decreases. As it comes down, its speed increases. Thus, it accelerates while coming down.

     

  • Question 7
    1 / -0

    Distance covered by a body from velocity-time graph is

    Solution

    Distance covered by a body from velocity-time graph is area under the graph.

     

  • Question 8
    1 / -0

    A cat runs around the boundary of a square field of side 6 m in 10 s. The displacement of the cat in 1 minute is

    Solution

    The displacement of the cat in 1 minute is zero as its initial and final position is same.

     

  • Question 9
    1 / -0

    How much distance a car covers when it moves 20 km East and then 60 km West?

    Solution

    As distance does not depend on direction. Hence, Total Distance = (20 + 60) km = 80 km.

     

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