Forces and Laws of Motion Test

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Forces and Laws of Motion Test - 50

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Question 1
1 / -0

"To every action, there is equal and opposite reaction". It is Newton's

A
First Law

B
Second Law

C
Third Law of Motion

D
None of these

Solution
Question 2
1 / -0

Which of the following statements is not true regarding the Newton's third law of motion?

A
To every action there is always an equal and opposite reaction.

B
Action and reaction act on the same body.

C
There is no cause-effect relation action and reaction.

D
Action and reaction forces are simultaneous forces.

Solution

Action and reaction act on the same body is not true regarding Newton's third law of motion. Action and reaction pairs always act on different bodies.
Hence,
option $$B$$ is the correct answer.
Question 3
1 / -0

Complete the statement of the first law of motion. "A body at rest stays at ____ and a body in motion stays in ____ unless an ____ is applied"

A
Motion; Rest; External Force

B
Rest; Motion; External Force

C
Rest; Motion; Internal Force

D
None of these

Solution

The first law of motion states "A body at rest stays at rest and a body in motion stays in motion unless an external force is applied"
Question 4
1 / -0

A ball is moving in the direction as shown. What will be the direction of momentum?

A
$$W$$

B
$$N$$

C
$$S$$

D
$$E$$

Solution

Since momentum $$p=mv$$

Direction of momentum is same as the direction of velocity. Hence, the direction of momentum of ball in the given case is East.
Question 5
1 / -0

Club the cases shown under balanced or unbalanced forces (all arrows represent same magnitude of force)

A
Balanced forces- $$A,B$$ and Unbalanced forces- $$C,D$$

B
Balanced forces- $$C,D$$ and Unbalanced forces- $$A,B$$

C
Balanced forces- $$A,C$$ and Unbalanced forces- $$B,D$$

D
Balanced forces- $$B,D$$ andUnbalanced forces- $$A,C$$

Solution

In cases $$B$$ and $$D$$, forces are equal and opposite. While, in cases $$A$$ and $$C$$, the forces are equal but not opposite.
Question 6
1 / -0

Find net force on the object shown in the figure. Will the object move?

A
$$F_{net} = 0$$; No

B
$$F_{net} \neq 0$$; No

C
$$F_{net} = 0$$; Yes

D
$$F_{net} \neq 0$$; Yes

Solution

Total force towards right $$= 20+6 = 26$$ units
Total force towards left $$= 13+13 = 26$$ units
So, net force $$(F_{net}) = 26-26 = 0$$
Hence, forces are balanced and the object will not move.
Question 7
1 / -0

Find net force on the object shown in the figure and answer if the forces are balanced or unbalanced

A
$$(F_{net}) = 0$$ ; Balanced Forces

B
$$(F_{net}) \neq 0$$; Balanced Forces

C
$$(F_{net}) = 0$$; Unbalanced Forces

D
$$(F_{net}) \neq 0$$; Unbalanced Forces

Solution

According to given fig.
Net horizontal force $$= 20-20 = 0$$ Unit
Net vertical force $$= 13-6 = 7$$ units
So, net force $$= 7$$ units (downward)
Hence, $$F_{net}\neq 0$$; forces are unbalanced,
Option D
Question 8
1 / -0

The momentum of a $$225\ g$$ ball moving at $$35 \ m/s$$ is

A
$$7875 \ kg \,m/s$$

B
$$3.5 \ N$$

C
$$5.0 \ m/s$$

D
$$7.875\ kg \ m/s$$

Solution

Given$$;$$
mass$$=225g$$ $$=0.225kg$$
velocity $$=35m/s$$
$$Momentum = mass \times velocity$$
$$ = 0.225 \times 35 = 7.875\,kg\,m/s$$
Hence,
option $$(D)$$ is correct answer.
Question 9
1 / -0

A fly strikes the windshield of a moving truck as shown. What can you say about the forces: the force on the fly and the force on the truck.

A
Force on the fly $$>$$ Force on the truck

B
Force on the fly $$<$$ Force on the truck

C
Force on the fly $$=$$ Force on the truck

D
None of these

Solution

From the third law of motion, Force on the fly (action) is equal and opposite to Force on the truck (reaction).
Question 10
1 / -0

Due to the application of a force on a body of mass $$100\ kg$$ that is initially at rest, the body moves with an acceleration of $$20{ms}^{-2}$$ in the direction of the force. Find the magnitude of the force.

A
$$1000N$$

B
$$2000N$$

C
$$3000N$$

D
$$4000N$$

Solution

Apply Newton's second law
$$F = ma$$
$$F$$ is net applied foorce
$$m$$ mass of the object
$$a$$ acceleration of the object
$$\Rightarrow F= 100\times 20$$
$$\Rightarrow F=2000 N$$