Some Basic Concepts of Chemistry Test

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Some Basic Concepts of Chemistry Test - 6

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Weekly Quiz Competition

Question 1
1 / -0

Calculate the weight of lime (CaO) obtained by heating 200 kg of 95% pure limestone (CaCO₃).

A
104.4 kg

B
105.4 kg

C
212.8 kg

D
106.4 kg
Question 2
1 / -0

20 m/s is the same as:

A
0.02 km/s

B
2000 mm/s

C
200 cm/s

D
0.002 mm/s

Solution

Since, 1000 m
= 1 km
∴ 20 m
= (20 ÷ 1000) km
= 0.02 km

Hence, 20 m / s = 0.02 km / s
1 km = 1000m
Question 3
1 / -0

30.4 cm = ---------- mm.:

A
3.04 mm

B
.0.030 mm

C
304 mm.

D
0.304 mm

Solution

Since,
1cm
=10 mm
∴ 30.4 cm
= (30.4 x 10) mm.
= 304 mm.
Question 4
1 / -0

Two students X and Y report the mass of the same substance as 7.0 g and 7.00 g, respectively. Which of the following statements is correct?

A
Both are equally accurate.

B
X is more accurate than Y.

C
Y is more accurate than X.

D
Both are inaccurate scientifically.
Question 5
1 / -0

We have to prepare a Litre solution of 0.2 M NaOH from the available 1 M solution.

What volume of 1M NaOH is required to be taken ?

A
2 mL

B
0.2 mL

C
200 mL

D
20 mL

Solution

Since,
total strength of given solution
= total strength of prepared solution
∴ Apply the relation - M1 x V1 = M2 x V2
where , M1= molarity of solution given= 1.0 M,
V1 = volume of solution given= ?
& M2= molarity of solution to be prepared = 0.20 M (given )
V2 = volume of solution to be prepared = 1000 mL ( given )
Substiuting the given values we get,
1.00M x V1 = 0.20 ×1000
V1= ( 0.20 × 1000) / 1.00
V1 = 200 mL
Question 6
1 / -0

In centigrade scale, -40 °F becomes

A
-20 °C

B
-40 °C

C
-25 °C

D
24 °C

Solution

Since , °F
= [ (°C x 9/5 ) + 32 ]
Substituting the given value of temperature in °F ,we get
-40°F
= ( °C x 1.8 )
∴ °C
= - (72 / 1.8 )
= -40°C
Question 7
1 / -0

The haemoglobin of most mammals contains approximately 0.33% of iron by mass. The molecular mass of haemoglobin is 67200. The number of iron atoms in each molecule of haemoglobin is

A
2

B
4

C
5

D
6
Question 8
1 / -0

Consider the chemical reaction given as,

-----CO (g) + ----- H₂(g) → ----- C₈H₁8(l) + ----- H₂O.

This equation can be balanced by inserting the following in blank spaces

A
8,2,8,17

B
8,17,1,8

C
8,8,1,17

D
8,2,1,17

Solution

The balanced equation for the given equation is,
8CO (g) + 17H₂ (g) → C₈H₁₈(l) + 8H₂O

hence , the coefficients ( 8 ,17 , 1, 8 ) are inserted on blank spaces ( from LHS to RHS )
Question 9
1 / -0

A mixture of CaCl₂ and NaCl weighing 4.44 g, when treated with sodium carbonate solution, precipitates all the calcium ions as calcium carbonate. The calcium carbonate so obtained is heated strongly to get 0.56 g of CaO.

The % of NaCl in the mixture is

A
31.5

B
75

C
25

D
40.2
Question 10
1 / -0

An object travels with a speed of 96 miles per hour. What is the speed of the object in SI units?

A
67.7 ms^-1

B
52.6 ms^-1

C
42.7 ms^-1

D
38.9 ms^-1
Question 11
1 / -0

A mixture of ethane and ethene occupies 41 L at 1 atm and 500 K. The mixture reacts completely with 10/3 moles of O₂ to produced CO₂ and H₂O. The mole fractions of ethane and ethene in the mixture respectively are ( R = 0.082 L atm mol^-1)

A
0.50 and 0.50

B
0.75 and 0.25

C
0.67 and 0.33

D
0.25 and 0.75
Question 12
1 / -0

Phosgene, a poisonous gas used during World War – I, contains 12.1% C, 16.2% O and 71.7% Cl by mass. What is its empirical formula?

A
COCl₂

B
CO₂Cl₂

C
COCl

D
None of these
Question 13
1 / -0

A certain gaseous mixture contains methane and sulphur dioxide in the ratio 1 : 8 by mass. The ratio of numbers of molecules is

A
1 : 8

B
1 : 2

C
1 : 1

D
2 : 1
Question 14
1 / -0

Which of the following sets of compounds correctly illustrates the law of reciprocal proportion?

A
P₂O₃, PH₃, H₂O

B
P₂O₅, PH₃, H₂O

C
N₂O₅, NH₃, H₂O

D
N₂O, NH₃, H₂O
Question 15
1 / -0

On dividing 0.86 by 16.564, the actual answer is 0.0519198. The correctly reported answer will be

A
0.05

B
0.051

C
0.0519

D
0.05191
Question 16
1 / -0

If 6 x 10²⁰ molecules of CO₂ are removed from 220 milligrams of CO₂, what is the number of remaining moles of CO₂?

A
2 x 10^-3 moles

B
3 x 10^-3 moles

C
4 x 10^-3 moles

D
5 x 10^-3 moles
Question 17
1 / -0

Two samples of sodium chloride are produced when sodium combines separately with two isotopes of chlorine ³⁵Cl and ³⁷Cl.

Which law is illustrated by the above facts?

A
Law of definite proportions

B
Law of multiple proportions

C
Gay Lussac's law

D
None of these
Question 18
1 / -0

Calculate the numbers of Cl^- and Ca²⁺ ions in 222 g of anhydrous CaCl₂.

A
2N ions of Ca²⁺ and 4N ions of Cl^-

B
2N ions of Cl^- and 4N ions of Ca²⁺

C
1N ions of Ca²⁺ and 1N ions of Cl^-

D
None of these
Question 19
1 / -0

If we consider that 1/6 in place of 1/12 mass of carbon atom is taken to be relative atomic mass unit, then the mass of one mole of a substance will

A
decrease twice

B
increase two folds

C
remain unchanged

D
be a fraction of molecular mass of the substance
Question 20
1 / -0

How many grams of concentrated nitric acid solution should be used to prepare 250 ml of 2.0 M HNO₃? The concentrated acid is 70% HNO₃.

A
54.0 g

B
45.0 g

C
90.0 g

D
70.0 g
Question 21
1 / -0

There are ____ cms. in 0.101 mm.?

A
1.010 cm

B
0.101 cms.

C
10.10 cm

D
0.0101 cms.

Solution
Question 22
1 / -0

15 km is = ---------------- m.?

A
1500 m

B
0.015 m

C
150 m

D
15000 m

Solution

Since,
1km
= 1000 m
∴ 15 km
= ( 15 x 1000 ) m
=15000 m
Question 23
1 / -0

How many years would it take to spend Avogadro's number of rupees at the rate of million rupees per second?

A
19. 098 x 10¹⁹ years

B
19.098 years

C
1.9098 x 10¹⁰years

D
None of these
Question 24
1 / -0

30 microliters is the same as:

A
0.03 mL

B
0.003 mL

C
0.0003 liters

D
3000000 liters

Solution

Since, 1 microliter
= 1 x10^-6 liters & 1ml
= 1 x 10^-3
∴ 1 microliter
= 0.001 mL
∴ 30 microliters
= ( 0.001 x 30 ) mL
= 0.03 mL
Question 25
1 / -0

Which of the following best explains the law of conservation of mass?

A
No change in mass is observed when 2.0 gm of Mg is burnt in vacuum.

B
1.2 g of carbon burnt in excess of oxygen consumes only 3.2 g of it and forms 4.4 g of CO₂.

C
12 g of carbon burnt in limited supply of air produces 20 g of carbon monoxide.

D
A sample of air on heating does not show any change in mass and its volume increases.
Question 26
1 / -0

Three flasks of equal volumes contain CH₄, CO₂ and Cl₂ gases. They will contain equal number of molecules if

A
the mass of all the gases is the same

B
the number of moles of all the gases is the same but the temperature is different

C
the temperature and pressure of all the flasks are the same

D
the temperature, pressure and mass of all the flasks are the same
Question 27
1 / -0

20 grams is the same as:

A
2000 mg

B
20000 mg

C
1500 mg

D
200 mg

Solution

Since,
1 g
= 1000 mg
∴ 20 g
= (20 x 1000 ) mg
= 20,000 mg
Question 28
1 / -0

Two oxides of a metal contain 36.4% and 53.4% of oxygen by mass. If the formula of the first oxide is M₂O, then that of the second is

A
M₂O₃

B
MO

C
MO₂

D
M₂O₅
Question 29
1 / -0

If 25 ml of a solution of barium hydroxide on titration with a 0.1 molar solution of hydrochloric acid gave a value of 35 ml, the molarity of barium hydroxide solution was

A
0.28 M

B
0.35 M

C
0.07 M

D
0.1 M
Question 30
1 / -0

There are ___ L in 12.0 ml?

A
0.0012 L

B
0.12 L

C
0.012 L

D
0.10 L

Solution

Since 1L
=1000 ml
∴ 12 ml
= (12 ÷ 1000) L
= 0.012 L

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Some Basic Concepts of Chemistry Test - 6

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Some Basic Concepts of Chemistry Test - 6

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Question 1

104.4 kg

105.4 kg

212.8 kg

106.4 kg

Question 2

0.02 km/s

2000 mm/s

200 cm/s

0.002 mm/s

Solution

Question 3

3.04 mm

.0.030 mm

304 mm.

0.304 mm

Solution

Question 4

Both are equally accurate.

X is more accurate than Y.

Y is more accurate than X.

Both are inaccurate scientifically.

Question 5

2 mL

0.2 mL

200 mL

20 mL

Solution

Question 6

-20 °C

-40 °C

-25 °C

24 °C

Solution

Question 7

2

4

5

6

Question 8

8,2,8,17

8,17,1,8

8,8,1,17

8,2,1,17

Solution

Question 9

31.5

75

25

40.2

Question 10

67.7 ms-1

52.6 ms-1

42.7 ms-1

38.9 ms-1

Question 11

0.50 and 0.50

0.75 and 0.25

0.67 and 0.33

0.25 and 0.75

Question 12

COCl2

CO2Cl2

COCl

None of these

Question 13

1 : 8

1 : 2

1 : 1

2 : 1

Question 14

P2O3, PH3, H2O

67.7 ms^-1

52.6 ms^-1

42.7 ms^-1

38.9 ms^-1

COCl₂

CO₂Cl₂

P₂O₃, PH₃, H₂O

P₂O₅, PH₃, H₂O

N₂O₅, NH₃, H₂O

N₂O, NH₃, H₂O

2 x 10^-3 moles

3 x 10^-3 moles

4 x 10^-3 moles

5 x 10^-3 moles

2N ions of Ca²⁺ and 4N ions of Cl^-

2N ions of Cl^- and 4N ions of Ca²⁺

1N ions of Ca²⁺ and 1N ions of Cl^-

19. 098 x 10¹⁹ years

1.9098 x 10¹⁰years

1.2 g of carbon burnt in excess of oxygen consumes only 3.2 g of it and forms 4.4 g of CO₂.