Parabola Test

Result

Parabola Test - 2

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Weekly Quiz Competition

Question 1
1 / -0

If the normal chord at a point 't' on the parabola y² = 4ax subtends a right angle at the vertex, then t² =

A
4

B
2

C
1

D
3
Question 2
1 / -0

The slopes of tangents drawn from a point (4, 10) to the parabola y² = 9x are

A
1/4, 3/4

B
1/4, 9/4

C
1/4, 1/3

D
None of these
Question 3
1 / -0

The straight line x + y = k touches the parabola y = x – x² if k equals

A
0

B
– 1

C
1

D
None of these
Question 4
1 / -0

Which of the following is an equation of a parabola?

A
y² = 6x² + 3x

B
y² = 6x⁴ + 3

C
y² = 6x² + 3

D
y² = 4x +4y
Question 5
1 / -0

The graph of which of the following polynomials will result in a parabola?

A
Cubic polynomial

B
Quadratic polynomial

C
Biquadratic polynomial

D
Linear polynomial
Question 6
1 / -0

The coordinates of an endpoint of the latus rectum of the parabola (y – 1)² = 4(x + 1) are

A
(0, – 3)

B
(0, – 1)

C
(0, 1)

D
(1, 3)
Question 7
1 / -0

Which of the following lie)s) on a parabola?

A
Focus of the parabola

B
Vertex of the parabola

C
Centre of the parabola

D
All of the above
Question 8
1 / -0

The equation(x²+y²)+5x−7y−2=0 represents

A
a circle

B
a pair of straight lines

C
an empty set

D
a degenerate circle

Solution

The general equation of the circle is x²+y²-2gh-2fy+c = 0. Sice the given equations satisfies the general equation, it represents the equation of the circle.

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Re-Attempt Weekly Quiz Competition

Parabola Test - 2

Result

Parabola Test - 2

Score

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Rank

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SHARING IS CARING

Question 1

4

2

1

3

Question 2

1/4, 3/4

1/4, 9/4

1/4, 1/3

None of these

Question 3

0

– 1

1

None of these

Question 4

y2 = 6x2 + 3x

y2 = 6x4 + 3

y2 = 6x2 + 3

y2 = 4x +4y

Question 5

Cubic polynomial

Quadratic polynomial

Biquadratic polynomial

Linear polynomial

Question 6

(0, – 3)

(0, – 1)

(0, 1)

(1, 3)

Question 7

Focus of the parabola

Vertex of the parabola

Centre of the parabola

All of the above

Question 8

a circle

a pair of straight lines

an empty set

a degenerate circle

Solution

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y² = 6x² + 3x

y² = 6x⁴ + 3

y² = 6x² + 3

y² = 4x +4y