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Trigonometry Test - 3

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Trigonometry Test - 3
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Weekly Quiz Competition
  • Question 1
    1 / -0

    The value of sin (45° + θ) – cos (45° – θ) is equal to

  • Question 2
    1 / -0

    If sinα = 1/2 and cosβ = 1/2, then the value of (α+β) is

  • Question 3
    1 / -0

    If sinθ – cosθ = 0, then what is the value of (sin4θ + cos4θ)? [Given (0º ≤ θ ≤ 90º)]

  • Question 4
    1 / -0

    The maximum value of sin x is

  • Question 5
    1 / -0

    The number of solutions of the equation 1 + sin x sin2 x/2= 0 in [-π, π]is

  • Question 6
    1 / -0

    The area of a triangle is 80cm2 and its perimeter is 8 cm. The radius of its inscribed circle is

    Solution

    We have if a,b,c are the sides of the triangle and r is the radius of the circle inscribed ,then

    r=△/s, where 2s=a+b+c and△ denotes the area of the triangle.

    Given △=80 and a+b+c=8

    ∴r=△/s=804=20cm

     

  • Question 7
    1 / -0

    tan x is periodic with period

  • Question 8
    1 / -0

    The magnitude of a radian is

  • Question 9
    1 / -0

    The perimeter of a triangle ABC is 6 times the arithmetic mean of the sines of its angles. If the side b is 2, then the angle B is

    Solution

    Givena+b+c={(14.PNG)}

    ⇒a+b+c=2(sinA+sinB+sinC)

    Now usings in erulea=ksinA,b=ksinB,c=ksinC⇒k(sinA+sinB+sinC)=2(sinA+sinB+sinC)⇒k=2 

    Now when b=2 we get

    sinB=bk=22=1⇒B=90∘

     

  • Question 10
    1 / -0

    If tan A = 1/2 and tan B = 1/3, then the value of sin (A + B) is

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