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Current Electricity Test - 1

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Current Electricity Test - 1
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  • Question 1
    1 / -0

    Two cells of 1.25 V and 0.75 V are connected in series with anode of one connected to anode of the other . The effective voltage will be

    Solution

    The cells are in opposition. 

    Eeq = E1 − E2 = 1.25 − 0.75 = 0.5V

     

  • Question 2
    1 / -0

    In a potentiometer experiment, for measuring internal resistance of a cell, the balance point has been obtained on the fourth wire. The balance point can be shifted to fifth wire by

    Solution

    If the current due to the auxillary battery is decreased, the potential gradient will be decreases, so the balancing length increases.
    Thus null point will move to fifth wire.

     

  • Question 3
    1 / -0

    A battery is connected with a potentiometer wire. The internal resistance of the battery is negligible. If the length of the potentiometer wire of the same material and radius is doubled then

    Solution

    Potential gradient Is given by V/l. If V and l are constant, the potential gradient also remains constant. The change in the radius will cause a change in the current. This does not change the potential gradient.

     

  • Question 4
    1 / -0

    The terminal potential difference of a cell is greater than its e.m.f. when it is

  • Question 5
    1 / -0

    The instrument for the accurate measurement of the e.m.f of a cell is

    Solution

    Both potentiometer and voltmeter are devices to measure potential difference. E M F is the terminal p.d between the electrodes of a cell in open circuit, i.e., when no current is drawn from it. Potentiometer measures the potential difference using null deflection method, where no current is drawn from the cell; whereas voltmeter needs a small current to show deflection. So, accurate measurement of p.d is done using a potentiometer.

     

  • Question 6
    1 / -0

    The resistivity of a wire depends upon

  • Question 7
    1 / -0

    The following question has four choices out of which ONLY ONE is correct.

    It is easier to start car engine on a hot day than on a cold day. This is because the internal resistance of the car battery

  • Question 8
    1 / -0

    An electric cell is

  • Question 9
    1 / -0

    Specific resistance of all metals is most affected by

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