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Integers Test - 7

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Integers Test - 7
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Simplify:

    (-33)×(96)(11)  × (-24)
    Solution

    -33×9611×-24(−3)×(−4)=12

  • Question 2
    1 / -0

    Evaluate−12 × 21

    Solution

    The product of a negative and a positive number is always anegative number.

    −12 × 21 = (−252)

    So option C is the correct answer.

  • Question 3
    1 / -0

    Withoutactual multiplication, then value of 175×175 – 25×25

    Solution

    175×175−25×25

    = (175)2− (25)2

    Using identity (a+b)(a−b)=a²−b²

    = (175+25) (175-25)

    = 200 × 150

    =30,000

    OptionB is correct.

  • Question 4
    1 / -0

    Thevalue of −5×−2×−2×−3 is

    Solution

    As there are 4 negative numbers, which is an even number,the product will be positive.

    So, −5 × −2 × −2 × −3 = 60

  • Question 5
    1 / -0

    −84×......=+84

    Solution

    (-84) x (-1) = (+84)

    Remember

    (-) x (-) = +

  • Question 6
    1 / -0

    (+132)÷ (−12)

    Solution

    (132)÷ (−12) = 132-12

    =12×11-12

    =-1×11

    =-11

    Option D is correct.

  • Question 7
    1 / -0

    Evaluate(−6) × (−2)

    Solution

    The product of two negative numbers is always a positivenumber.

    So, −6 × (−2) = +12

    So option D is the correct answer.

  • Question 8
    1 / -0

    -112× _______=+112

    Solution

    −112×(−1)=+112

  • Question 9
    1 / -0

    Divide(−54)×(64) by (−27)×(−128)

    Solution

    (−54) × (64) ÷ (−27) × (−128)

    = −3456 ÷ 3456

    = −1

  • Question 10
    1 / -0

    Forany integer a, a+0=

    Solution

    The additive identity property says that if you add aninteger to zero or add zero to an integer, then you get the same integer back.The number zero is known as the identity element, or the additive identity. Forexample, for any integer aa,

    a + 0 = 0 + a = a

    Hence, for any integer a, a + 0 = a.

  • Question 11
    1 / -0

    68 ×____ = -68

    Solution

    68 ×(−1)=−68

  • Question 12
    1 / -0

    Signof the product of 789 negative integers and 7 positive integers is

    Solution

    Since 789 is an odd number, the product of 789 negativeintegers will be negative.

    The product of all positive integers is a positivenumber. Hence, the product of 7 positive integers will be a positive integer.

    Therefore,the product of the two integers (789 negative and 7 positive) of unlike signswill be negative.

  • Question 13
    1 / -0

    Multiply4×(−3)×(−2) and 6×(−5)

    Solution

    4 × (−3) × (−2) × 6 × (−5)

    = 24 × −30

    = −720

  • Question 14
    1 / -0

    Thevalue of −5×−12×2×−3 is

    Solution

    As there are 3 negative numbers, which is an odd number, theproduct will be negative.

    So, −5 × −12 × 2 × −3 = −360.

  • Question 15
    1 / -0

    Thenegative integer whose product with −1 is-

    Solution

    The positive integer product with −1 is positive.

    For example: -2 × (−1) = 2 and -2.5 × (−1) = 2.5.

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