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Fractions and Decimals Test - 5

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Fractions and Decimals Test - 5
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  • Question 1
    1 / -0

    Add-3.007, 0.587 and 18.341

    Solution

    3.007, 0.587 and 18.341

    So we get

    3.007 + 0.587 + 18.341 = 21.935

  • Question 2
    1 / -0

    The cost of one kg of sugar increases from ₹38.47 to ₹42.65. Find the increase in cost.

    Solution

    Cost of sugar = ₹38.47

    Cost of sugar is raised = ₹42.65

    Increase in the cost of sugar = ₹42.65 – ₹38.47 = ₹4.18

  • Question 3
    1 / -0

    Add- 6. 08, 60.8, 0.608 and 0.0608

    Solution

    6.08, 60.8, 0.608 and 0.0608 

    So we get

    6.08 + 60.8 + 0.608 + 0.0608 = 67.5488

  • Question 4
    1 / -0

    Add- 9.25, 3.4 and 6.666

    Solution

    9.25, 3.4 and 6.666

    So we get 

    9.25 + 3.4 + 6.666 = 19.316

  • Question 5
    1 / -0

    What is the excess of 65 over 38.29?

    Solution

    We know that the excess of 65 over 38.29 can be written as

    65-38.29=26.71

    Hence, the excess of 65 over 38.29 is 26.71.

  • Question 6
    1 / -0

    Find the difference between 7.85 and 1.685.

    Solution

    The difference between 7.85 and 1.685 = 7.85 – 1.685

    = 6.165

  • Question 7
    1 / -0

    Add- 0.2, 0.02 and 2.0002

    Solution

    0.2, 0.02 and2.0002

    So we get

    0.2 + 0.02 + 2.0002= 2.2202

  • Question 8
    1 / -0

    What is the excess of 484.29 over 113.95?

    Solution

    It is given that

    Sum of two numbers = 484.29

    One number = 113.95

    So the other number = 484.29 – 113.95 = 370.34

  • Question 9
    1 / -0

    What should be added to 49.587 to give 80.375?

    Solution

    It is given that

    Sum of two numbers = 80.375

    One number = 49.587

    So the other number = 80.375 – 39.587 = 30.788

  • Question 10
    1 / -0

    If A = 237.98 and B = 83.47.

    Find: 

    (i) A – B
    (ii) B – A.

    Solution

    A – B

    It is given that A = 237.98 and B = 83.47

    Substituting the values

    A – B = 237.98 – 83.47

    A – B = 154.51

    (ii) B – A

    It is given that A = 237.98 and B = 83.47

    Substituting the values

    B – A = 83.47 – 237.98

    B – A = – 154.51

  • Question 11
    1 / -0

    Multiply 0.5 number by 1000: 

    Solution

    It can be written as

    0.5 × 10 = 5

    0.5 × 100 = 50

    0.5 × 1000 = 500

  • Question 12
    1 / -0

    Add 29.03, 0.0003, 0.3 and 7.2

    Solution

    29.03, 0.0003, 0.3 and 7.2

    So we get

    29.03 + 0.0003 + 0.3 + 7.2 = 36.5303

  • Question 13
    1 / -0

    Take out the sum of 29.38 and 46.025, then subtract it from 200.111.

    Solution

    We know that the sum of 29.38 and 46.025 can be written as

    29.38 + 46.025 = 75.405

    We can write it as

    Difference between 200.111 and 75.405

    200.111 – 75.405 = 124.706

  • Question 14
    1 / -0

    What should be subtracted from 100 to give 29.29?

    Solution

    It is given that

    Sum of two numbers = 100

    One number = 19.29

    So the other number = 100 – 29.29 = 70.71

  • Question 15
    1 / -0

    Add 3.4, 2.025, 9.36 and 3.6221

    Solution

    3.4, 2.025, 9.36 and 3.6221 

    So we get

    3.4 + 2.025 + 9.36 + 3.6221 = 18.4071

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