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Fractions and Decimals Test - 8

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Fractions and Decimals Test - 8
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  • Question 1
    1 / -0

    Add- 0.651, 0.254 and 0.125

    Solution

    0.651, 0.254 and 0.125

    So we get

    0.651+0.254+0.125 = 1.03

  • Question 2
    1 / -0

    If A = 983.146 and B = 753.568.
    Find: B + A.

    Solution

    B + A

    It is given that A = 983.146 and B = 753.568

    Substituting the values

    B + A = 983.146 + 753.568

    B + A = 1736.714

  • Question 3
    1 / -0

    Add 2.03, 0.3 and 34.2

    Solution

    2.03, 0.3 and 34.2

    So we get

    2.03 + 0.3 + 34.2 = 36.53

  • Question 4
    1 / -0

    If A = 983.146 and B = 753.568.

    Find: A – B (ii) B – A.

    Solution

    A – B

    It is given that A = 983.146 and B = 753.568

    Substituting the values

    A – B = 983.146-753.568

    A – B = 229.578

  • Question 5
    1 / -0

    Multiply 6.42 by 3.8: 

    Solution

    It can be written as

    6.42 x 3.8 =24.396

  • Question 6
    1 / -0

    Take out the sum of 32.26 and 35.85, then subtract it from 100.

    Solution

    We know that the sum of 32.26 and 35.85 can be written as

    32.26 + 35.85 = 68.11

    We can write it as

    Difference between 100 and 68.11

    100-68.11 = 31.89

  • Question 7
    1 / -0

    Add- 0.8, 0.08 and 0.608

    Solution

    0.8, 0.08 and 0.608 

    So we get

    0.8 + 0.08 + 0.608 = 1.488

  • Question 8
    1 / -0

    What is the excess of 85 over 58.29?

    Solution

    We know that the excess of 85 over 58.29 can be written as

    85-58.29=26.71

    Hence, the excess of 85 over 58.29 is 26.71.

  • Question 9
    1 / -0

    What should be subtracted from 256.235 to give 188.253?

    Solution

    It is given that,

    Sum of two numbers = 256.235

    One number = 188.253

    So the other number = 256.235-188.253 = 67.982

  • Question 10
    1 / -0

    The cost of a packet of tea increases from ₹429.25 to ₹440.55. Find the increase in cost.

    Solution

    Cost of tea = ₹429.25

    Cost of tea is raised = ₹440.55

    Increase in the cost of sugar = ₹440.55 – ₹429.25 = ₹11.3

  • Question 11
    1 / -0

    Multiply 0.253 by 0.14:

    Solution

    It can be written as

    0.253 × 0.14 = 0.03542

  • Question 12
    1 / -0

    Add- 2.025, 0.36 and 0.622

    Solution

    2.025, 0.36 and 0.622

    So we get

    2.025 + 0.36 + 0.622 = 3.007

  • Question 13
    1 / -0

    What should be added to 65.256 to give 124.359?

    Solution

    It is given that

    Sum of two numbers = 124.359

    One number = 65.256

    So the other number = 124.359-65.256 = 59.103

  • Question 14
    1 / -0

    What is the excess of 351.966 over 15.226?

    Solution

    It is given that

    Sum of two numbers = 351.966

    One number = 15.266

    So the other number = 351.966-15.266 = 336.74

  • Question 15
    1 / -0

    Find the difference between 9.875 and 3.256.

    Solution

    The difference between 9.875 and 3.256 = 9.875-3.256

    =6.619

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