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Exponents Test - 6

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Exponents Test - 6
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Weekly Quiz Competition
  • Question 1
    1 / -0

    26 __82

    Solution

    The expansion of 26 = 2 × 2 × 2 ×2 × 2 × 2 = 64

    The expansion of 82 = 8 × 8= 64

    Clearly,

    256 = 64

    So, 26= 82

    Hence, both numbers are equal numbers.

  • Question 2
    1 / -0

    615 ÷610= 6---

    Solution

    615 ÷ 610= 6---

    By the rule of dividing the powers with same base = am ÷ an = am – n

    Then,

    = (6)15 – 10

    = 65

  • Question 3
    1 / -0

    540= ___

    Solution

    Factors of 540 = 2 × 2 × 3 × 3 × 3 × 5

    = 22 × 33 × 5

  • Question 4
    1 / -0

    53 __35

    Solution

    The expansion of 53 = 5 × 5 × 5 =125

    The expansion of 35 = 3 × 3 × 3 ×3 × 3= 243

    Clearly,

    125 < 243

    So, 53 < 35

    Hence 35 is the greater number.

  • Question 5
    1 / -0

    2.7 × 1012 __  1.5 × 108

    Solution

    By observing the question

    Comparing the exponents of base 10,

    Clearly,

    2.7 × 1012 > 1.5 × 108

  • Question 6
    1 / -0

    72 ×22= ___

    Solution

    The above question can be written as,

    = 7 × 7 × 2 × 2

    = 49 × 4

    = 196

  • Question 7
    1 / -0

    648 = ___

    Solution

    Factors of 648 = 2 × 2 × 2 × 3 × 3 × 3 × 3

    = 23 × 34

  • Question 8
    1 / -0

    ___ = (–3)2 ×(–5)2

    Solution

    The expansion of (-3)2 × (-5)2

    = – 3 × – 3 × – 5 × – 5

    = 9 × 25

    = 225

  • Question 9
    1 / -0

    ___ =(– 4)3

    Solution

    The expansion of -43

    = – 4 × – 4 × – 4

    = – 64

  • Question 10
    1 / -0

    3--- = 32 ×34 ×38

    Solution

    By the rule of multiplying the powers with same base = am × an = am + n

    Then,

    = (3)2 + 4 + 8

    = 314

  • Question 11
    1 / -0

    (23 ×34 ×4)/ (3 × 32)= 3---

    Solution

    Factors of 32 = 2 × 2 × 2 × 2 × 2

    = 25

    Factors of 4 = 2 × 2

    = 22

    Then,

    = (23 × 34 × 22)/ (3 × 25)

    = (23 + 2 × 34) / (3 × 25) … [∵am × an = am + n]

    = (25 × 34) / (3 × 25)

    = 25 – 5 × 34 – 1 … [∵am ÷ an = am – n]

    = 20 × 33

    = 1 × 33

    = 33

  • Question 12
    1 / -0

    3,600= ____

    Solution

    Factors of 3600 = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 5

    = 24 × 32 × 52

  • Question 13
    1 / -0

    23 ×5= _____

    Solution

    The above question can be written as,

    = 2 × 2 × 2 × 5

    = 8 × 5

    = 40

  • Question 14
    1 / -0

    ___ = (–3) × (–2)3

    Solution

    The expansion of (-3) × (-2)3

    = – 3 × – 2 × – 2 × – 2

    = – 3 × – 8

    = 24

  • Question 15
    1 / -0

    2 × 103= ____

    Solution

    The above question can be written as,

    = 2 × 10 × 10 × 10

    = 2 × 1000

    = 2000

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