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Percent and Percentage Test - 7

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Percent and Percentage Test - 7
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  • Question 1
    1 / -0

    In an examination, first division marks are 50%. Astudent secures 448 marks and misses the first division by 2 marks. Find thetotal marks of the examination.

    Solution

    Marks for first division = 50%

    A student gets 530 marks and misses the first division by 2marks

    Marks for first division = 448 + 2 = 450

    50% of total marks = 450

    We can write it as

    50/100 × total marks = 450

    So we get

    Total marks = (450 × 100)/ 50 = 900

  • Question 2
    1 / -0

    7 is what percent of 28

    Solution

    It can be calculated as,

    (7/28) x 100

    = (1/4) x 100

    = 25

  • Question 3
    1 / -0

    Whatis the new value if 5 is increased by 300%?

    Solution

    Given Value = 5

    300 % of 5= 5 x 300/100

    =15

    New value = 5 + 15

    = 20.

  • Question 4
    1 / -0

    Thenumber which exceeds double of 6% of it by 52.8 is:

    Solution

    Doubleof 6% = 12%. So,
    Let the number be x. Then, x – 12% of x = 52.8
    x – (12/100)x = 52.8
    x (1– 12/100) = 52.8
    (88/100)x = 52.8
    x = (100 X 52.8) / 88 = 60

  • Question 5
    1 / -0

    What will be the fraction of 20% 

    Solution

    It will

    20 x1/100

    = 1/5

  • Question 6
    1 / -0

    What percent of 60 m is 9 m?

    Solution

    Let a % of 60 m = 9 m

    Step 1 – Convert the Percentage into Fraction
    i.e. a % = a/100

    Step 2– Multiply the Fraction with given quantity.

    60a/100=9

    a = 90/6

    a = 15
    Hence, 9 m is 15 % of 60 m

  • Question 7
    1 / -0

    84% of a number is 28. Find the number.

    Solution

    Consider x as the number

    84% of x = 28

    We can write it as

    84/100 × x = 28

    By further calculation

    84x = 28 × 100

    So we get

    x =28.5

  • Question 8
    1 / -0

    If L = a% of b and M = b% of a, then which ofthe following is true?

    Solution

    a % of b = (a x b)/100

    b % of a = (b x a)/100

    From the above we can saythat,

    L=M

  • Question 9
    1 / -0

    A fruit seller had some apples. He sells 60% apples which are equal to 420 apples. Originally, he had:

    Solution

    Suppose originally hehad a apples.

    So,

    a x 60/100 = 420

    a = 4200/6

    a = 700.

  • Question 10
    1 / -0

    What will be the fraction of 4% 

    Solution

    It will be

    4 x 1/100

     = 1/25.

  • Question 11
    1 / -0

    5.25 can be expressed in terms of percentage as

    Solution

    While calculation in termsof percentage we need to multiply by 100,

    So,

    5.25 x 100

    = 525.

  • Question 12
    1 / -0

    Aman has a certain unknown sum of money, 40 % of that sum is ₹ 3200. What is thesum of money?

    Solution

    The problem can be solved using linear equation.
    Let the unknown sum of money be ₹ a
    We know, that 40 % of ₹ a = ₹ 3200

    40 % x a = ₹ ( 3200 )
    40/100 x a = ₹ ( 3200 )

    a = ₹ (3200 x 100)/40

    = ₹ 8000
    Therefore, the unknown sum of money available with the man is ₹ 8000

  • Question 13
    1 / -0

    A number when decreased by 20 % gives 40. The number is?

    Solution

    Solution: Here we take the help of linear equation. Firstwe will form the equation.
    Let the number be ‘a’
    So,

    From the question

    a-(20a/100) = 40

    (100a-20a)/100 =40

    a = 50
    Hence, the number is 50

  • Question 14
    1 / -0

    What percentage of numbers from 1 to 20 have 2 or 3 in the unit's digit?

    Solution

    There are only four numbersas given below:

    2, 3, 12 and 13

    So,

    The required percentage =(4/20) x 100

    =20

  • Question 15
    1 / -0

    Find71 % of 3600 meters

    Solution

    Step 1 – Convert the Percentage into Fraction
    i.e. 71 % = 71/100

    Step 2– Multiply the Fraction with givenquantity.
    i.e., (71/100 x 3600) meters = 2556 meters.

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